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svet-max [94.6K]
3 years ago
12

What is the solution to this equation? 2 x + 3 = x − 4

Mathematics
2 answers:
maksim [4K]3 years ago
6 0

Answer:

-7

Step-by-step explanation:

Mrrafil [7]3 years ago
4 0

Answer:

the answer is -7

Step-by-step explanation:

hope this helps

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Write 6.3 x 10^4 in standard notation.
icang [17]
The power of 4 means to move the decimal 4 places to the right. 6.3 x 10^4
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Bc has endpoints b(5 ,9) and c(-4, -3). Find the coordinates of the midpoint of bc
Alex73 [517]
We can find the midpoint of any line segment using the midpoint formula: M=(x1+x2/2,y1+y2/2). Essentially, the midpoint formula finds the average of two points. If we use B and the first point and C as the second, when we plug in our values we would have M=(5-4/2,9-5/2). This can be simplified to M=(1/2,4/2) or M=(1/2,2) which is the final answer.

<span>I hope this helps.</span>
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What is two solutions for x&gt;6
Daniel [21]

7>6

8>6

9>6

etc.

Possible values for x:

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x=8

x=9

etc.

4 0
3 years ago
Suppose we have 3 cards identical in form except that both sides of the first card are colored red, both sides of the second car
Nikolay [14]

Answer:

probability that the other side is colored black if the upper side of the chosen card is colored red = 1/3

Step-by-step explanation:

First of all;

Let B1 be the event that the card with two red sides is selected

Let B2 be the event that the

card with two black sides is selected

Let B3 be the event that the card with one red side and one black side is

selected

Let A be the event that the upper side of the selected card (when put down on the ground)

is red.

Now, from the question;

P(B3) = ⅓

P(A|B3) = ½

P(B1) = ⅓

P(A|B1) = 1

P(B2) = ⅓

P(A|B2)) = 0

(P(B3) = ⅓

P(A|B3) = ½

Now, we want to find the probability that the other side is colored black if the upper side of the chosen card is colored red. This probability is; P(B3|A). Thus, from the Bayes’ formula, it follows that;

P(B3|A) = [P(B3)•P(A|B3)]/[(P(B1)•P(A|B1)) + (P(B2)•P(A|B2)) + (P(B3)•P(A|B3))]

Thus;

P(B3|A) = [⅓×½]/[(⅓×1) + (⅓•0) + (⅓×½)]

P(B3|A) = (1/6)/(⅓ + 0 + 1/6)

P(B3|A) = (1/6)/(1/2)

P(B3|A) = 1/3

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3 years ago
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Gregs because Inches are greater in value than centimeters.
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