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Elenna [48]
3 years ago
15

a ball is tossed into the air from a height of 8 feet with an initial velocity of 8 feet per second. Find the time t(in seconds)

it takes for the object to reach the ground by solving the equation -16t^2+8t+8=0
Mathematics
1 answer:
Nat2105 [25]3 years ago
8 0
So first you need to factor and get 8( t-1 ) (2t+1)=0. Then you need to divide both sides by 8 to isolate the equation. 0/8=0 so ( t-1 ) (2t+1)=0. Next set each of the factors = to 0 and get t-1=0 and 2t+1=0. Solve, and get t=1 and t=-1/2. The negative does not apply so you know it takes 1 second for the ball to hit the ground. 
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