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Black_prince [1.1K]
3 years ago
5

An atom of Iron has at least three different isotopes. What is the difference between an isotope of 55Fe and an isotope of 58Fe?

Chemistry
1 answer:
11Alexandr11 [23.1K]3 years ago
6 0
The isotopes 55Fe and 58Fe are both Iron, but have a different atomic mass due to the added number of neutrons. Both isotopes have 26 protons, but 55Fe has more neutrons.
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A sample of ascorbic acid (vitamin C) is synthesized in the laboratory. It contains 30.0 g carbon and 40.0 g oxygen. Another sam
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Answer:

16.933g approximately 17.0 grams

Explanation:

From the simple promotions and given the same compound ascorbic acid (vitamin C)

In the laboratory synthesised ascorbic acid

Mass of carbon = 30.0g

Mas of Oxygen = 40.0g

That is the mass of Oxygen per unit mass of Carbon

Per gram of Carbon we have

(30.0g Carbon)÷30 combines with (40.0g of Oxygen)÷30

That is 4/3g of Oxygen per gram of Carbon

Hence the mass of Oxygen compound that combines with 12.7g of Carbonin natural occurring ascorbic acid (vitamin C) is = 4/3×12.7 = 16.933g approximately 17.0g

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3 years ago
What’s the number 9.1x10^3 in standard form
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Answer:

.0091

Explanation:

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Can you identify 2 characteristics of combustion reactions?
monitta
An element or compound will react with oxygen and will produce carbon dioxide, water, and sometimes carbon (if it is an incomplete combustion).
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3 years ago
Describe the term molarity as it relates to an acid or base.
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Molarity is expressed as the number of moles of solute per volume of the solution. For example, we are given a solution of 2M NaOH this describes a solution that has 2 moles of NaOH per 1 L volume of the solution. Acids and bases can be measured through the concentrations of H+ and OH- ions in units of molarity. Hope this helps.
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Read 2 more answers
Determine the heat of reaction (ΔHrxn) for the combustion of ethanol (C2H5OH) by using heat of formation data: C2H5OH (l) + 3 O2
egoroff_w [7]

Answer:

\Delta H_{rxn}=-1234.782kJ

Explanation:

\Delta H_{rxn}=\sum [n_{i}\times \Delta H_{f}^{0}(product)_{i}]-\sum [n_{j}\times \Delta H_{f}^{0}(reactant_{j})]

Where n_{i} and n_{j} are number of moles of product and reactant respectively (equal to their stoichiometric coefficient).

\Delta H_{f}^{0} is standard heat of formation.

So, \Delta H_{rxn}=[2mol\times \Delta H_{f}^{0}(CO_{2})_{g}]+[3mol\times \Delta H_{f}^{0}(H_{2}O)_{g}]-[1mol\times \Delta H_{f}^{0}(C_{2}H_{5}OH)_{l}]-[3mol\times \Delta H_{f}^{0}(O_{2})_{g}]

or, \Delta H_{rxn}=[2mol\times -393.509kJ/mol]+[3mol\times -241.818kJ/mol]-[1mol\times -277.69kJ/mol]-[3mol\times 0kJ/mol]

or, \Delta H_{rxn}=-1234.782kJ

4 0
3 years ago
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