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3 years ago

Once at the top. the wax molecules begin to___________ energy to the glass then the surrounding air.

Chemistry

1 answer:

8_murik_8 [283]3 years ago

3 0

Answer:

release

Explanation:

A that is the answer

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What is the name of the compound N2(g)

zavuch27 [327]

N2 stands for nitrogen.
this compound also includes the exact mass.
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3 years ago

) A children’s liquid cold medicine has a density of 1.23 g/mL. If a child is to take 2.5 tsp in a dose, what is the mass in gra

vekshin1

The relation between density and mass and volume is

$Density=\frac{Mass}{volume}$

the dose required is 2.5 tsp

each tsp contain 5mL

So dose required in mL = 2.5 X 5 = 12.5 mL

the mass will be calculated using following formula

$Mass=DensityXvolume$

$Mass=1.23\frac{g}{mL}X12.5mL= 15.38g$

The mass of dose in grams will be 15.38 g

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3 years ago

When you add water to calcium oxide it makes calcium hydroxide

Romashka [77]

Yes you add water to calcium oxide it makes calcium hydroxide

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3 years ago

Why is it important to assume that the rate of radioactive decay has remained constant over time?

alexira [117]

It remains constant because it is an element. Just like Chernobyl, there is still active radiation. Radiation is something that stays in the air for a verrrry long time. <span>Radioactivity kill cells, so lets say you have your phone on but its in your pocket.the radiation from the phone is killing your cells.</span>

4 0

3 years ago

Object A specific heat is 2.45 J/g C and object B specific heat is 0.82 J/g C. Which object will heat up more if they have the s

Artist 52 [7]

Answer: Object B will heat up more.

Explanation:

The formula for specific heat is as follows.

Q = $m C \Delta T$

Where,

Q = heat provided

m = mass

C = specific heat

$\Delta T$ = change in temperature

Now, both the objects have same mass and equal amount of heat is applied.

According to the formula, the equation will be as follows.

$Q_{1}$ = $Q_{2}$

$m C_{1}\Delta T$ = $m C_{2}\Delta T_{2}$

Cancel m from both sides, as mass is same. Therefore,

$C_{1} (T_{f} - T_{i})_A$ = $C_{2}(T_{f} - T_{i})_B$

Cancel out the initial temperature and put the values of specific heat, then the equation will be as follows.

$2.45 (T_{f})_A$ = $0.82(T_{f})_B$

Therefore, from the above equation it can be concluded that the object with low specific heat will heat up more as its specific heat will be inversely proportional to its final temperature.

Hence, object B will heat up more.

4 0

3 years ago