Answer:
In the presence of a base, blue litmus paper will turn red........
We are told that KOH is being used to completely neutral H₂SO₄ according to the following reaction:
KOH + H₂SO₄ → H₂O + KHSO₄
If KOH can completely neutralize H₂SO₄, then there must be an equal amount of moles of each as they are in a 1:1 ratio:
0.025 L x 0.150 mol/L = .00375 mol KOH
0.00375 mol KOH x 1 mole H₂SO₄/1 mole KOH = 0.00375 mol H₂SO₄
We are told we have 15 mL of H₂SO₄ initially, so now we can find the original concentration:
0.00375 mol / 0.015 L = 0.25 mol/L
The concentration of H₂SO₄ being neutralized is 0.25 M.
Answer:
I would say there would be 5-10% in a city, and maybe 10-20% in the country. It mainly varies depending on how big the city is, how many people/districts there are, and the size of the country, which makes it hard to give a certain percent of shops, as there may be small businesses included as well or new shops being built.
Hope this helps! This was pretty confusing for me as well so i hope the answer is alright (×﹏×)
I believe this question has the following five choices to
choose from:
>an SN2 reaction has occurred with inversion of
configuration
>racemization followed by an S N 2 attack
>an SN1 reaction has taken over resulting in inversion
of configuration
>an SN1 reaction has occurred due to carbocation
formation
>an SN1 reaction followed by an S N 2 “backside”
attack
The correct answer is:
an SN1 reaction has occurred due to carbocation formation
Answer:
It's well Explained below.
Explanation:
First of Excess product of CaCO_3 would be produced due to the fact that there would not be enough CaCl_2 to react with Na_2•CO_3. The main purpose of having stoichiometric quantities is for us to know the correct amount or near the correct amount of each reactant in order to create a product that will be close to the theoretical amount and thus have a higher percent yield.
