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3 years ago

V1t2 = v2t1 is an expression of

Chemistry

1 answer:

Lesechka [4]3 years ago

5 0

Answer:

v1t1 = v2t2 is Charles law

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Solid sodium reacts violently with water, producing heat, hydrogen gas, and sodium hydroxide. How many molecules of hydrogen gas

Zinaida [17]

Answer: Number of molecules of hydrogen gas $6.32\times 10^{32}$

Explanation:

$2Na+2H_2O\rightarrow 2NaOH+H_2$

Number of moles of sodium = $\frac{\text{mass of sodium}}{\text{molar mass of sodium}}=\frac{48.7 g}{23 g/mol}=2.11mol$

According to reaction , 2 moles of sodium produces 1 mole of hydrogen gas , then 2.11 mol of sodium will= $\frac{1}{2}\times 2.11 mol$ of hydrogen gas that is 1.05 moles of hydrogen gas.

Number of molecules = $N_A(\text{Avogadro number})\times$ moles of substance

Moles of hydrogen gas formed = 1.05 moles

Number of molecules of hydrogen gas = $N_A\times$ moles of hydrogen gas

Number of molecules of hydrogen gas $=6.022\times 10^{23} mole^{-1}\times 1.05 mole=6.32\times 10^{32}$

8 0

3 years ago

babunello [35]

The correct answer is Chemical energy changes to mechanical energy. Chemical energy in the battery powers the mechanical fan. ON USA TEST PREP!!!!!

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3 years ago

Identify an anion. an atom that has gained a proton. an atom that has gained an electron. an atom that has lost an electron. an

Finger [1]

I THINK it's gained a proton

6 0

4 years ago

if a plot weight (in g) vs. volume (in ml) for a metal gave the equation y= 13.41x and r^2=0.9981 what is the density of the met

Bumek [7]

ANS: density = 13.41 g/ml

Density (d) of a substance is the mass (m) occupied by it in a given volume (v).

Density = mass/volume

i.e. d = m/v

m = (d) v -----(1)

The given equation from the plot of weight vs volume is :

y = 13.41 x ----(2)

Based on equations (1) and (2) we can deduce that the density of the metal is 13.41 g/ml

8 0

4 years ago

Read 2 more answers

Construct a three-step synthesis of 1,2-epoxycyclopentane from cyclopentanol by dragging the appropriate formulas into the bins.

vladimir2022 [97]

Answer:

(1) Bromination, (2) E2 elimination and (3) epoxidation

Explanation:

In the first step, -OH group in cyclopentanol is replaced by more facile leaving group Br by treating cyclopentanol with $PBr_{3}$

In the second step, E2 elimination in presence of strong base e.g. NaOEt/EtOH produce cyclopentene

In the third step, treatment of cyclopentene with mCPBA produces 1,2-epoxycyclopentane

Full reaction scheme has been shown below

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3 years ago