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Andrej [43]
3 years ago
14

A rocket initially at rest accelerates at a rate of 90 m/s 2 for 0.7 min. What is its speed at the end of this time? Answer in u

nits of m/s.
Physics
1 answer:
alexira [117]3 years ago
7 0

Answer:

Final speed of the rocket, v = 3780 m/s

Explanation:

It is given that,

Initial speed of the rocket, u = 0 (at rest)

Acceleration of the rocket, a=90\ m/s^2

Time taken, t = 0.7 min = 42 s

We need to find the speed at the end of this time. It can be calculated using first equation of motion as :

v=u+at

v=90\times 42

v = 3780 m/s

So, the speed of the rocket at the end at the end of 0.7 minutes is 3780 m/s. Hence, this is the required solution.

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Answer:

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Explanation:

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this differential equation has a solution of type

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we substitute

          4π² f² = ρ_liquid g π r² / m

          f = \frac{1}{2\pi } \ \sqrt{ \frac{ \rho_{liquid} \  \pi  r^2 \ g}{m } }

calculate

         f = \frac{1}{2 \pi }  \sqrt{ \frac{ 1000 \ \pi  \ 0.03^2 \ 9.8 }{0.025}  }

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