Question

A rocket initially at rest accelerates at a rate of 90 m/s 2 for 0.7 min. What is its speed at the end of this time? Answer in units of m/s.

Answer 1

Answer:

Final speed of the rocket, v = 3780 m/s

Explanation:

It is given that,

Initial speed of the rocket, u = 0 (at rest)

Acceleration of the rocket, $a=90\ m/s^2$

Time taken, t = 0.7 min = 42 s

We need to find the speed at the end of this time. It can be calculated using first equation of motion as :

$v=u+at$

$v=90\times 42$

v = 3780 m/s

So, the speed of the rocket at the end at the end of 0.7 minutes is 3780 m/s. Hence, this is the required solution.