Question

You leave on a 450 miles trip in order to attend a meeting that will start 10.8 hours after you begin your trip. Along the way you plan to stop for dinner. If the fastest you can safely drive is 55 mi/h, what is the longest time you can spend over dinner and still arrive just in time for the meeting? Select one: O a. 0.8 h b. You can't stop at all. c. 2.6 h d. 2.8 h 0

Answer 1

Answer:

c. 2.6 h

Explanation:

The longest time spent over dinner is the time that you have available minus the minimum possible time spent in the trip.

The time of the trip is found using:

t = $\frac{d}{v}$

Where distance is d and velocity is v. The time will be minimum at maximum velocity. Replacing with the data we have:

Ttrip = $\frac{450}{55}$ = 8.1818 h

Tdinner = 10.8h - 8.1818 h = 2.6181h

that aproximates 2.6 h.