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Alborosie
3 years ago
14

You leave on a 450 miles trip in order to attend a meeting that will start 10.8 hours after you begin your trip. Along the way y

ou plan to stop for dinner. If the fastest you can safely drive is 55 mi/h, what is the longest time you can spend over dinner and still arrive just in time for the meeting? Select one: O a. 0.8 h b. You can't stop at all. c. 2.6 h d. 2.8 h 0
Physics
1 answer:
konstantin123 [22]3 years ago
4 0

Answer:

c. 2.6 h

Explanation:

The longest time spent over dinner is the time that you have available minus the minimum possible time spent in the trip.

The time of the trip is found using:

t = \frac{d}{v}

Where distance is d and velocity is v. The time will be minimum at maximum velocity. Replacing with the data we have:

Ttrip = \frac{450}{55} = 8.1818 h

Tdinner = 10.8h - 8.1818 h = 2.6181h

that aproximates 2.6 h.

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The particle with sharp ends have the slowest rate of deposition  

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If the sound level at a point is 98.0 dB, what is the intensity of sound at that point (Unit=W/m^2)? please help will give brain
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0.006309573 w/m^2.

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What magnification will be produced by a lens of power –4.00 D (such as might be used to correct myopia) if an object is held 43
kiruha [24]

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The magnification is m  = 0.3674

Explanation:

From the question we are told that

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  The object distance is u =  -43 \ cm the negative sign is because the distance is measured in the opposite direction of incident light (i.e away )

 Generally the focal length is mathematically represented as

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   =>f = \frac{1}{4.00 }  

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6 0
2 years ago
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Answer:

Distance will be =3960\times 0.12385=490.468miles

Explanation:

We have given that Buffalo has a latitude of 42.9°N

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Difference in their latitudes = 42.9-35.8=7.1^{\circ}

Now changing the angle in radian = 7.1\times\frac{\pi }{180}=0.12385radian

So distance will be =3960\times 0.12385=490.468miles

5 0
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