The origin of the universe remains a question. true false

An experimental 1500-kg car travels at a constant speed of 22 m/s around a circular test track that is 80 m across. What is the

stepladder [879]

Answer:

363000 J or 363 kJ

Explanation:

Because the car is not rotating, it has no rotational kinetic energy. Its kinetic energy is then simply

$\frac{1}{2} mv^2 = \frac{1}{2}\times1500\times22^2 = 363000 \text{ J}$

8 0

4 years ago

Different color ca

777dan777 [17]

Answer: The color of candy cane

Explanation:

An independent variable is the Variable that the scientist changed in order to change the dependent variable. The scientist changes the color of the candy cane to test the rate at which they dissolve.

4 0

4 years ago

The terminal velocity of a person falling in air depends upon the weight and the area of the person facing the fluid. Find the t

yuradex [85]

Answer: 104.026 m/s=374.49 km/h

Explanation:

When a body or object falls, basically two forces act on it:

1. The force of air friction, also called "drag force" $D$ :

$D={C}_{d}\frac{\rho V^{2} }{2}A$ (1)

Where:

$C_ {d}=0.7$ is the drag coefficient

$\rho=1.21 kg/m^{3}$ is the density of the fluid (air in this case)

$V$ is the velocity

$A=0.17 m^{2}$ is the transversal area of the object

So, this force is proportional to the transversal area of the falling element and to the square of the velocity.

2. Its weight due to the gravity force $W$ :

$W=m.g$ (2)

Where:

$m=79.5 kg$ is the mass of the object

$g=9.8 m/s^{2}$ is the acceleration due gravity

<h3>So, at the moment when the drag force equals the gravity force, the object will have its terminal velocity: </h3>

$D=W$ (3)

${C}_{d}\frac{\rho V^{2} }{2}A=m.g$ (4)

$V=\sqrt{\frac{2m.g}{\rho A{C}_{d}}}$ (5) This is the terminal velocity

Substituting the known values in (5):

$V=\sqrt{\frac{2(79.5 kg)(9.8 m/s^{2})}{(1.21 kg/m^{3})(0.17m^{2}){(0.7)}}$ (6)

Then:

$V=104.026 m/s$ This is the final velocity in meters per second

Now, let's find the final velocity in kilometers per hour, knowing $1 km=1000 m$ and $1 h=3600 s$ :

$V=104.026 \frac{m}{s} (\frac{1 km}{1000 m})(\frac{3600 s}{1 h})=374.49 km/h$ This is the final velocity in kilometers per hour.

4 0

3 years ago

What aggression hormone is found not active in animals versus humans

Alika [10]

Answer:

For some dog owners, a leisurely walk can turn stressful the moment their canine companion sees another pup walking by. Dogs with what is known as "leash aggression" may bark, growl or lunge at other dogs during walks, setting the scene for a tense and potentially dangerous interaction.

4 0

3 years ago

A satellite is in orbit 3.117106 m from the center of Earth. The mass of Earth is 5.9821024 kg. Calculate the orbital

Dahasolnce [82]

Answer:

T = 1733.16 s = 28.88 min

Explanation:

The orbital velocity of a satellite about Earth is given as follows:

$v = \sqrt{\frac{GM}{R}}$