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2 years ago

Would the energy of the wave increase or decrease if the speed of the wave increases? Why?

1 answer:

4 0

Answer: The energy of a wave increases with an increase in the amplitude of the wave. The energy of a wave decreases with an increase in the amplitude of a wave.

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If Earth were the size of a grape, how big would the Moon be? How far away would the Moon be from the Earth? How large would the

dangina [55]

Answer:

The moon would be the size of a raspberry. It would be as far a like 4 or 5 inches. The sun would be as big as an cantaloupe.The sun would be as far as 10 or 11 inches.

Explanation:

3 0

3 years ago

Coherent light with wavelength 598 nm passes through two very narrow slits, and the interference pattern is observed on a screen

Stella [2.4K]

Answer:

1.196 μm

Explanation:

D = Screen distance = 3 m

$\lambda$ = Wavelength = 598 m

y = Distance of first-order bright fringe from the center of the central bright fringe = 4.84 mm

d = Slit distance

$tan\theta=\frac{y}{D}\\\Rightarrow \theta=tan^{-1}{\frac{y}{D}}\\\Rightarrow \theta=tan^{-1}{\frac{4.84\times 10^{-3}}{3}}\\\Rightarrow \theta=0.09243\ ^{\circ}$

$sin\theta=\frac{\lambda}{d}\\\Rightarrow d=\frac{\lambda}{sin\theta}\\\Rightarrow d=\frac{598\times 10^{-9}}{sin0.09243}\\\Rightarrow d=0.00037066\ m$

For first dark fringe

$dsin\theta=\frac{\lambda'}{2}\\\Rightarrow \lambda'=2dsin\theta\\\Rightarrow \lambda'=2\times 0.00037066\times sin0.09243\\\Rightarrow \lambda'=1.196\times 10^{-6}\\\Rightarrow \lambda'=1.196\ \mu m$

Wavelength of first-order dark fringe observed at this same point on the screen is 1.196 μm

3 0

2 years ago

Sound is an example of ?

wlad13 [49]

Aaaaaaaaaaaaaaaaaaaaaaaaaaaaaa

8 0

3 years ago

Read 2 more answers

A racecar driver has to hold on tightly when going around a banked curve. Approximately what is the centripetal force on a 2220.

g100num [7]

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4 0

3 years ago

A 20 liter cylinder of helium at a pressure of 150 atm and a temperature of 27ÁC is used to fill a balloon at 1.00 atm and 37ÁC.

djyliett [7]

<u>Answer</u>

D) 3100 Liters

<u>Explanation</u>

To get the volume if the balloon you need to use the combined equation of the low of gases.

P₁V₁/T₁ = P₂V₂/T₂

(20×150)/(27+273) = (1×V₂)/(37+273)

3000/300 = V₂/310

10 = V₂/310

V₂ = 10 × 310

= 3100 Liters

7 0

3 years ago

Read 2 more answers