Net ionic: 2Ag+(aq) + SO4(aq) --> Ag2SO4(s)
balanced: 2 AgNO3(aq) + H2So4(aq) —> Ag2SO4(s) + 2 HNO3(aq)
Answer:
Alkali metals
Explanation:
The lowest number of valence electrons is found in the alkali metals (group 1), which have only one valence electron per atom.
Answer:
Now u have 48 g of O2. There. Fore mole=weight/M. W. Of oxygen. Therefor 3mole.
After that if we to multiply the avogadro number with it. So 3 *NA
Now u want only atom calculation then we have 2 molecule of oxygen then multiply it with 2 too.
So final claculation is =3*2*NA.
Explanation:
your welcome
brainlest PLEASEEEEEEE!
Answer:
I think its B im not sure
but i hope this helps