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Naddika [18.5K]
4 years ago
9

Why can a liquid change to take the shape of its container but NOT expand to fill the container itself?

Physics
2 answers:
Rom4ik [11]4 years ago
6 0
Because it cant expand it can only change its shape
Simora [160]4 years ago
3 0

Answer:

C)  because the particles of a liquid are held together loosely enough to flow, but not so loose that they expand  

Explanation:

took the test

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Photons of what minimum frequency are required to remove electrons from gold? note: the work function for gold is 4.8 ev.
kolbaska11 [484]
In the photoelectric effect, the energy given by the incoming photon is used partially to extract the electron from the metal (work function) and the rest is converted into kinetic energy of the electron:
hf= \phi + K
where
hf is the energy of the photon, with h being the Planck constant and f the frequency of the photon
\phi is the work function
K is the kinetic energy of the electron

When K=0, we have the minimum energy required to extract the electron from the metal, so the equation becomes
hf= \phi (1)

If we convert the work function of gold into Joules:
\phi=4.8 eV = 7.69 \cdot 10^{-19}J
We can re-arrange eq.(1) to find the minimum energy of the photon:
f= \frac{\phi}{h}= \frac{7.69 \cdot 10^{-19}J}{6.6 \cdot 10^{-34} Js} =1.17 \cdot 10^{15} Hz
5 0
4 years ago
If you catch the ruler 4.9 cm from the lower end, what is your reaction time?
Luba_88 [7]

Answer:

0.10s

Explanation:

the fall time is

4.9/100=.5*9.81*t^2

solve for t

6 0
3 years ago
Calculate the ratio of the drag force on a jet flying at 950 km/h at an altitude of 10 km to the drag force on a prop-driven tra
Black_prince [1.1K]

Answer:

\frac{F_1}{F_2}=3.55

Explanation:

F = Force

C = Drag coefficient equal for both aircrafts

ρ = Density of air

A = Surface area equal for both aircrafts

v = Velocity

v_2=\frac{2}{5}v_1

F_1=\frac{1}{2}\rho_1 CAv_1^2

F_2=\frac{1}{2}\rho_2 CAv_2^2\\\Rightarrow F_2=\frac{1}{2}\rho_2 CA\left(\frac{2}{5}v_1\right)^2

Dividing the above two equations we get

\frac{F_1}{F_2}=\frac{\frac{1}{2}\rho_1 CAv_1^2}{\frac{1}{2}\rho_2 CA\left(\frac{2}{5}v_1\right)^2}\\\Rightarrow \frac{F_1}{F_2}=\frac{\rho_1}{\rho_2\frac{4}{25}}\\\Rightarrow \frac{F_1}{F_2}=\frac{0.38}{0.67\frac{4}{25}}\\\Rightarrow \frac{F_1}{F_2}=3.55

The ratio of the drag forces is \mathbf{\frac{F_1}{F_2}}=\mathbf{3.55}

5 0
3 years ago
Eating a banana enables s person to perform about 4×10⁴ J of work. To what vertical height does eating a banana enable a 50kg wo
rjkz [21]

Answer:

80m

Explanation:

potential energy = MGH

p.e = 50 X 10 X h

4x10⁴ = 500 X h

h = 4x10⁴/500

h = 80m

6 0
3 years ago
Why do opposite charges attract and like charges repel?
baherus [9]
They attract if they are oppositely charged and they repel if they have the same charges.
4 0
3 years ago
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