Explanation:
Use the formula:
e is the energy released,
m is the mass of water,
c is the specific heat capacity,
δθ is the change in temperature ( 100 - 22)
A fuel cell combines hydrogen and oxygen to produce electricity, heat, and water. Fuel cells are often compared to batteries. Both convert the energy produced by a chemical reaction into usable electric power.
Answer:
The total power radiated by the sun is 3.71×10^26W
Explanation:
The Earth is spherical in shape
Therefore, Area = 4πr^2 = 4×3.143×(1.489×10^11)^2 = 2.79×10^23m^2
Power radiated by the Sun = solar radiation on Earth × Area = 1330W/m^2 × 2.79×10^23m^2 = 3.71×10^26W
The volume of the tire at the given diameter and thickness of tube is determined as 1,128.2 cubic inch.
<h3>What is volume?</h3>
Volume is a scalar quantity expressing the amount of three-dimensional space enclosed by a closed surface.
<h3>
Volume of the tire</h3>
The volume of the tire is the measure of the product of area and thickness of the tire.
The volume of the tire is calculated as follows;
Radius of the tire = 0.5 x 26" = 13"
Volume of the tire = Area x thickness
Volume of the tire = πr² x h
where;
- r is the radius of the tire
- h is the thickness of the tube
Volume of the tire = π(13)² x (2.125)
Volume of the tire = 1,128.2 cubic inch
Thus, the volume of the tire at the given diameter and thickness of tube is determined as 1,128.2 cubic inch.
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Answer:
C. 2.5 A
Explanation:
Transformer: A transformer is an electromechanical device that is used to change the voltage of an alternating current.
The current and the number of loops in a transformer is related as shown below
Ns/Np = Ip/Is........................... Equation 1
Where Ns = Secondary loop, Np = primary loop, Ip = primary current, Is = secondary current.
Making Is the subject of the equation
Is = NpIp/Ns........................ Equation 2
Given: Np = 10 loops, Ns = 20 loops, Ip = 5.0 A.
Substitute into equation 2
Is = (10×5.0)/20
Is = 50/20
Is = 2.5 A.
Hence the current in the primary coil = 2.5 A.
The right option is C. 2.5 A
