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Andreyy89
3 years ago
8

Which activity would be the best choice foir a lifelong fitness program

Physics
2 answers:
Fantom [35]3 years ago
7 0

I think jogging/running/walking because you don't need any equipment and you can structure around it on your own time.

Xelga [282]3 years ago
6 0

Answer:

I would say walking or running  

Explanation:

Because its simple and you can choose your own pace

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Imagine you had a bar of gold and decided to cut in half. You repeated this process until eventually you could no longer cut the
nydimaria [60]

This would prove that gold is an <em>element</em>.  No matter how far down you
examine it, you never find any particles of anything except gold.

An example of a different case is salt. 
-- Imagine you had a block of salt and decided to cut it in half.
-- If you repeated this process, then eventually, at some point, you'd have
a tiny particle of salt in front of you, just like before.  BUT ...
-- Just as you were getting ready to cut this one in half, you'd notice that this
particle of salt is different.  It's one atom of sodium stuck to one atom of chlorine,
and if you cut it in half, you would not have ANY salt.   <span />

This would prove that salt is a <em><u>compound</u></em>, made of atoms of two or more elements.

3 0
4 years ago
Read 2 more answers
According to newtons first law,if no net force acts on a object,the object continues in motion with?
Dovator [93]
The object keps going cause of wind friction
6 0
4 years ago
Read 2 more answers
Verena is mixing a material into a beaker filled with a liquid. She notices that the material seems to disappear into the liquid
leonid [27]

She observes solubility - the ability of the substance to dissolve in e.g. the liquid.

4 0
4 years ago
A supersonic nozzle is also a convergent–divergent duct, which is fed by a large reservoir at the inlet to the nozzle. In the re
Lady_Fox [76]

Answer:

155.38424 K

2.2721 kg/m³

Explanation:

P_1 = Pressure at reservoir = 10 atm

T_1 = Temperature at reservoir = 300 K

P_2 = Pressure at exit = 1 atm

T_2 = Temperature at exit

R_s = Mass-specific gas constant = 287 J/kgK

\gamma = Specific heat ratio = 1.4 for air

For isentropic flow

\frac{T_2}{T_1}=\frac{P_2}{P_1}^{\frac{\gamma-1}{\gamma}}\\\Rightarrow T_2=T_1\times \frac{P_2}{P_1}^{\frac{\gamma-1}{\gamma}}\\\Rightarrow T_2=00\times \left(\frac{1}{10}\right)^{\frac{1.4-1}{1.4}}\\\Rightarrow T_2=155.38424\ K

The temperature of the flow at the exit is 155.38424 K

From the ideal equation density is given by

\rho_2=\frac{P_2}{R_sT_2}\\\Rightarrow \rho=\frac{1\times 101325}{287\times 155.38424}\\\Rightarrow \rho=2.2721\ kg/m^3

The density of the flow at the exit is 2.2721 kg/m³

4 0
3 years ago
Find α, the angular acceleration of the wheel, which results from F⃗ pulling the string to the left. Use the standard convention
kap26 [50]

Answer:

α = F/(k×m×r)

Explanation:

When the wheel is pulled to turn in a counterclockwise direction, the wheel will have a moment of inertia given by Iw = k×m×r²

Where k = the radius of gyration of the wheel which is a dimensionless quantity less than one.

m = the mass of the wheel

r = the radius of the wheel

First and foremost, we relate the torque (τ) about the axle of the wheel to the force (F) applied on the wheel and we have that τ = r × F

We then relate the torque on the wheel to the angular acceleration (α), we have that τ = Iw × α, where Iw is the moment of inertia of the wheel as explained above

Substituting for torque τ and moment of inertia I into the above equation we have that

r × F = k×m×r² × α

solving for α we have that

α = r × F /(k×m×r²)

Therefore

α = F/(k×m×r)

8 0
4 years ago
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