We will solve this problem using the direct concept related to band gap energy, that is, a band gap is the distance between the valence band of electrons and the conduction band, i. e, the energy range in a solid where no electron states (Electronic state) can exist Mathematically can be described as,

Where,
h = Planck's constant
n = Energy level
mc = Effective mass of the point charge
R = Size of the particle
As you can see the energy is inversely proportional to the size of the particle:

Therefore if the size is decreased, the amount of energy is increased.
Answer:
-450 m/s
Explanation:
Momentum is conserved.
p₀ = p
0 = (1.5 kg) (1.5 m/s) + (0.005 kg) v
v = -450 m/s
The correct answer is option B, representational
All the painters in Peale family were involved in paintings which represent the day today life activities or were portraits or mimic some natural forms.
Charles Willson Peale , the head of the Peale family was known for painting sixty portraits of the first American president, George Washington. He also painted portraits of portraits of notable people of the society such as Benjamin Franklin, Thomas Jefferson etc.
Most of the paintings of peale family were based on the theme of family, art and science. Six of Peale’s son were known for their renaissance paintings. His oldest son Raphelle was known for still life paintings.
Titian Ramsay Peale, Charles’ youngest son was a naturalist painter.
Answer:
East of North
Explanation:
We have the following data:
Speed of the wind from East to West: 
Speed of the bee relative to the air: 
If we graph these speeds (which in fact are velocities because are vectors) in a vector diagram, we will have a right triangle in which the airspeed of the bee (its speed relative to te air) is the hypotense and the two sides of the triangle will be the <u>Speed of the wind from East to West</u> (in the horintal part) and the <u>speed due North relative to the ground</u> (in the vertical part).
Now, we need to find the direction the bee should fly directly to the flower (due North):


Clearing
:

