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Angelina_Jolie [31]
3 years ago
13

The number if particles in one molecule is?

Chemistry
1 answer:
igomit [66]3 years ago
5 0
6.022 x 10^23 particles in one molecule
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Two very stable compounds, Freon-12 and Freon-14, are used as liquid refrigerants. A Freon-12 molecule consists of one carbon at
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82. Freon-12 and Freon-14 are called halocarbons or just halides. 


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Pressure does not affect the voltage produced in a voltaic cell.

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How does the presence of a catalyst affect the enthalpy of a reaction? Group of answer choices 1. It depends on whether you are
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Answer:

Option 3. The catalyst does not affect the enthalpy change (\Delta H_\text{rxn}) of a reaction.

Explanation:

As its name suggests, the enthalpy change of a reaction (\Delta H_\text{rxn}) is the difference between the enthalpy of the products and the reactants.

On the other hand, a catalyst speeds up a reaction because it provides an alternative reaction pathway from the reactants to the products.

In effect, a catalyst reduces the activation energy of the reaction in both directions. The reactants and products of the reaction won't change. As a result, the difference in their enthalpies won't change, either. That's the same as saying that the enthalpy change \Delta H_\text{rxn} of the reaction would stay the same.

Refer to an energy profile diagram. Enthalpy change of the reaction \Delta H_\text{rxn} measures the difference between the two horizontal sections. Indeed, the catalyst lowered the height of the peak. However, that did not change the height of each horizontal section or the difference between them. Hence, the enthalpy change of the reaction stayed the same.

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3 years ago
A gas exerts a pressure of 350.0 torr at 20.0 Celsius. What would be the new pressure in atmospheres if the temperature is raise
IgorC [24]

Answer:

373.88 torr

Explanation:

P1 = 350 torr

T1 = 20°C = (20 + 273.15)K = 293.15K

P2 = ?

T2 = 40°C = (40 + 273.15)K = 313.15K

From pressure law,

Pressure of a given mass of gas is directly proportional to its temperature.

P = KT

K = P / T

P1 / T1 = P2 / T2

Solve for P2

P2 = (P1 * T2) / T1

P2 = (350 * 313.15) / 293.15

P2 = 109602.5 / 293.15

P2 = 373.878 torr

P2 = 373.88 torr

The new pressure of the gas would be 373.88 torr.

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