Answer:
6 Percent Composition. 1. Molar Mass of KBr K = 1(39.10) = 39.10 Br =1(79.90) =79.90 MM = 119.0 79.90 g 119.0 g = 0.6714 3. 0.6714 x 50.0g = 33.6 g Br 2.
there are valence electrons 3 in group 10.
Well you didn’t post any but I’m hoping that either plastic, lead, wood, glass, or paper, are an option.
Answer: The empirical formula for the given compound is ![CH_5N](https://tex.z-dn.net/?f=CH_5N)
Explanation : Given,
Percentage of C = 38.8 %
Percentage of H = 16.2 %
Percentage of N = 45.1 %
Let the mass of compound be 100 g. So, percentages given are taken as mass.
Mass of C = 38.8 g
Mass of H = 16.2 g
Mass of N = 45.4 g
To formulate the empirical formula, we need to follow some steps:
Step 1: Converting the given masses into moles.
Moles of Carbon =![\frac{\text{Given mass of Carbon}}{\text{Molar mass of Carbon}}=\frac{38.8g}{12g/mole}=3.23moles](https://tex.z-dn.net/?f=%5Cfrac%7B%5Ctext%7BGiven%20mass%20of%20Carbon%7D%7D%7B%5Ctext%7BMolar%20mass%20of%20Carbon%7D%7D%3D%5Cfrac%7B38.8g%7D%7B12g%2Fmole%7D%3D3.23moles)
Moles of Hydrogen = ![\frac{\text{Given mass of Hydrogen}}{\text{Molar mass of Hydrogen}}=\frac{16.2g}{1g/mole}=16.2moles](https://tex.z-dn.net/?f=%5Cfrac%7B%5Ctext%7BGiven%20mass%20of%20Hydrogen%7D%7D%7B%5Ctext%7BMolar%20mass%20of%20Hydrogen%7D%7D%3D%5Cfrac%7B16.2g%7D%7B1g%2Fmole%7D%3D16.2moles)
Moles of Nitrogen = ![\frac{\text{Given mass of nitrogen}}{\text{Molar mass of nitrogen}}=\frac{45.4g}{14g/mole}=3.24moles](https://tex.z-dn.net/?f=%5Cfrac%7B%5Ctext%7BGiven%20mass%20of%20nitrogen%7D%7D%7B%5Ctext%7BMolar%20mass%20of%20nitrogen%7D%7D%3D%5Cfrac%7B45.4g%7D%7B14g%2Fmole%7D%3D3.24moles)
Step 2: Calculating the mole ratio of the given elements.
For the mole ratio, we divide each value of the moles by the smallest number of moles calculated which is 3.23 moles.
For Carbon = ![\frac{3.23}{3.23}=1](https://tex.z-dn.net/?f=%5Cfrac%7B3.23%7D%7B3.23%7D%3D1)
For Hydrogen = ![\frac{16.2}{3.23}=5.01\approx 5](https://tex.z-dn.net/?f=%5Cfrac%7B16.2%7D%7B3.23%7D%3D5.01%5Capprox%205)
For Oxygen = ![\frac{3.24}{3.23}=1.00\approx 1](https://tex.z-dn.net/?f=%5Cfrac%7B3.24%7D%7B3.23%7D%3D1.00%5Capprox%201)
Step 3: Taking the mole ratio as their subscripts.
The ratio of C : H : N = 1 : 5 : 1
Hence, the empirical formula for the given compound is ![C_1H_5N_1=CH_5N](https://tex.z-dn.net/?f=C_1H_5N_1%3DCH_5N)
For the question given above, option 2 which is H-Cl pair of atoms has the most polar bond among the four of them.
The larger the value of the electronegativity, the greater the atom’s strength to attract a bonding pair of electrons. <span>Hydrogen has an electronegativity of 2.1, and chlorine has an electronegativity of 3.0. The electron pair that is bonding HCl together shifts toward the chlorine atom because it has a larger electronegativity value.</span>