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3 years ago

What best explains why sodium is more likely to react with another element than an element such as neon?

Chemistry

2 answers:

nexus9112 [7]3 years ago

8 0

sodium has one fewer electron than neon

hichkok12 [17]3 years ago

5 0

Answer:

1 fewer electron

Explanation:

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Maggie is solving a chemistry riddle her clue is to take the number of valence electrons in halogens and subtract it by the numb

Novay_Z [31]

The answer to the riddle Maggie is solving is 6

To determine the answer to the riddle Maggie is solving,

We will subtract the number of valence electrons in halogens by the number of valence electrons in alkali metals.

First, let us define what is meant by valence electrons

Valence electrons are those electrons that reside in the outermost shell surrounding an atomic nucleus.

Now, we will the determine the respective number of valence electrons in halogens as well as the number of valence electrons in alkali metals.

For Halogens

Halogens are the group 17 (group 7A) elements in the periodic table. Examples are Fluorine, Chlorine, Bromine etc.

Halogens have 7 electrons in their outermost shell

For Alkali metals

Alkali metals are the group 1 metals. Examples are Lithium, Sodium, Potassium etc.

Alkali metals have 1 electron in their outermost shell

Now, for the answer to the riddle,

Answer to the riddle = Number of valence electrons in halogens - Number of valence electrons in Alkali metals

Answer to the riddle = 7 - 1

∴ Answer to the riddle = 6

Hence, the answer to the riddle Maggie is solving is 6

Learn more here: brainly.com/question/9392364

6 0

3 years ago

What is the oxidation number of s in na2s4o6?

Novosadov [1.4K]

Answer:

+2.5

Explanation:

So the oxidation number of S in Na2S4O6is +2.5.

7 0

3 years ago

Read 2 more answers

How many moles of Ag can be produced if 350. g of Cu are reacted with excess AgNO3 according to the equation Cu(s) + 2AgNO3(aq)

Ksju [112]

Hello.

balance the equation first
Cu + 2AgNO3 ----> [2Ag] + Cu(NO3)2


Now set up the equation 
350gCu*(1molCu/ 63.546g Cu) * (2molAg/1molCu) * (107.8682g Ag/1molAg)


Cancel out 1molCu with 1molCu, and cancel out 2molAg with 1molAg (it still remains 2mol Ag) 

You are left with 
350gCu*(1/63.546g Cu)*(2Ag/1)* (107.8682g Ag/1)


350gCu*1*2*107.8682= 75507.74g


now divide 75507.74g by 63.546g

you get [1188.2374972460896g Ag]

Have a nice day

3 0

3 years ago

Read 2 more answers

Explain why the product at the negative electrode is not always a metal.

Elena-2011 [213]

Answer:

Whether you get the metal or hydrogen during electrolysis depends on the position of the metal in the reactivity series: the metal will be produced if it is less reactive than hydrogen. hydrogen will be produced if the metal is more reactive than hydrogen.

3 0

3 years ago

"A certain group one metal combines with Hydrogen, to form a molecule with the formula XH. The equilibrium bond length of this c

Tasya [4]

Based on the bond length, the molecular weight of the unknown metal X is 23.

<h3>What are ionic compounds?</h3>

Ionic compounds are compounds which are formed between oppositely charged ions.

When hydrogen combines with the group 1 metals, they form ionic compounds.

The group one metals that combine with hydrogen to firm ionic bonds include:

Lithium to give Lithium hydride with equilibrium bond length of 0.239Å.
Sodium to give sodium hydride with equilibrium bond length of 1.896Å.
Potassium to give potassium hydride with equilibrium bond length of 2.321Å

The molecular weight of lithium is 7 g

The molecularweight of sodium is 23

The molecular weight of Potassium is 39.

Therefore, based on the equilibrium bond length, the molecular weight of the unknown metal X is 23.

Learn more about bond length at: brainly.com/question/3405662

5 0

3 years ago