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4 years ago

How far below an initial straight-line path will a projectile fall in one second

Physics

1 answer:

Anni [7]4 years ago

3 0

Answer:

9.8 m

Explanation:

The rate of free fall of a body does not depend on its mass or shape in the absence of air resistance. This property of gravitational force is proved by the famous leaning tower of Pisa experiment by Galileo.

The gravitational force is responsible for the gravitational acceleration of a body.

When considering the gravitational acceleration near the surface of Earth it has the constant value g = 9.8 m/s irrespective of the mass of the body.

This phenomenon states that every projectile falls at the same rate such that its velocity keeps on increasing to maintain the constancy of g.

So, when a projectile fall initially from a certain height for one second, it would have traveled only 9.8 m.

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At the periphery of a hurricane the air is ____, and several kilometers above the surface, in the eye, the air is ____.

tatuchka [14]

<span>At the periphery of a hurricane the air is sinking, and several kilometers above the surface, in the eye, the air is sinking. </span>

6 0

4 years ago

What is the frequency of the fundamental mode of vibration of a steel piano wire stretched to a tension of 440 N? The wire is 0.

Rasek [7]

Complete Question

The complete question is shown on the first uploaded image

Answer:

Explanation:

From the question we are told that

The tension is $T = 440 \ N$

The length of the wire is $l = 0.600 \ m$

The mass is $m = 5.60 \ g = 0.0056 \ kg$

Generally the frequency is mathematically represented as

$f = \frac{1}{2l} * \sqrt{\frac{T}{\frac{m}{l} } }$

=> $f = \frac{1}{2 * 0.600 } * \sqrt{\frac{440}{\frac{0.0056}{0.600} } }$

=> $f = 181 \ Hz$

4 0

3 years ago

A plane travels at a speed of 205mph in still air. Flying with a tailwind, the plane is clocked over a distance of 1000 miles. F

vaieri [72.5K]

While plane is moving under tailwind condition it took time "t"

so here we will have

$t = \frac{d}{v_{net}}$

here net speed of the plane will be given as

$v_{net} = v + v_w$

$t = \frac{1000}{205 + v_w}$

similarly when it moves under the condition of headwind its net speed is given as

$v_{net} = v - v_w$

now time taken to cover the distance is 2 hours more

$t + 2 = \frac{1000}{205 - v_w}$

now solving two equations

$\frac{1000}{205 + v_w} + 2 = \frac{1000}{205 - v_w}$

solving above for v_w we got

$v_w = 40.4 mph$

6 0

3 years ago

How is an experiment is actually conducted

NeX [460]

By using the scientific method

3 0

3 years ago

What is the density of a rock that has a mass of 454g and volume of 100.0cm

Mademuasel [1]

Answer:

4.54 g/cm3

Explanation:

7 0

3 years ago