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yawa3891 [41]
3 years ago
12

Tony waits for the spring tide to bring the best surfing waves in his area. He knows that the moon affects the tides, so which m

oons does he wait for?
A. waxing and waning crescent moons
B. new moon and full moon
C. first and third quarter moons
D. waxing and waning gibbous moons
Physics
2 answers:
Komok [63]3 years ago
8 0

Answer:

c

Explanation:

just looked it up

guajiro [1.7K]3 years ago
6 0

Answer:

C

Explanation:

You might be interested in
The difference between relational and reactive aggression is that relational aggression is ______, whereas reactive aggression i
givi [52]

Answer:

Social, physical behavior

Explanation:

The relational aggression is the aggression which caused or give to person by doing harm to his or her relationship or social image.

Reactive aggression is the aggression which is caused by threatening someone, or caused by provocation, or caused due to frustration.

Therefore, the basic  differentiation in  between both the aggression is that relational aggression is caused by by damaging social status whereas reactive aggression is caused through physical behavior.

8 0
3 years ago
When air is blown across the top of an open
Tanzania [10]
When air is blown across the top of an open <span>water bottle, air molecules in the bottle vibrate at a particular frequency and sound is produced in a process called "refraction". 
</span>
8 0
3 years ago
Defination of formula bar​
Gekata [30.6K]

The Formula Bar is where data or formulas you enter into a worksheet appear for the active cell. The Formula Bar can also be used to edit data or formula in the active cell. The active cell displays the results of its formula while we see the formula itself in the Formula Bar.

mark me brainliestt :))

7 0
2 years ago
Read 2 more answers
A ball is dropped from a rooftop 60m high. <br> How long is the ball in the air?
alina1380 [7]

Answer: 3.49 s

Explanation:

We can solve this problem with the following equation of motion:

y=y_{o}+V_{o}t-\frac{1}{2}gt^{2} (1)

Where:

y=0 m is the final height of the ball

y_{o}=60 m is the initial height of the ball

V_{o}=0 m/s is the initial velocity (the ball was dropped)

g=9.8 m/s^{2} is the acceleratio due gravity

t is the time

Isolating t:

t=\sqrt{\frac{2 y_{o}}{g}} (2)

t=\sqrt{\frac{2 (60 m)}{9.8 m/s^{2}}} (3)

Finally we find the time the ball is in the air:

t=3.49 s (4)

7 0
3 years ago
A 500kg car skids to a stop at a traffic light, leaving behind a 18.25m skid mark as it comes to a rest. Assuming that the car i
Nastasia [14]

Answer:

Coefficient of friction will be 0.587

Explanation:

We have given mass of the car m = 500 kg

Distance s = 18.25 m

Initial velocity of the car u = 14.5 m/sec

As the car finally stops so final velocity v = 0 m/sec

From second equation of motion

v^2=u^2+2as

0^2=14.5^2+2\times a\times 18.25

a=-5.76m/sec^2

We know that acceleration is given by

a=\mu g

5.76=\mu\times  9.81

\mu =0.587

So coefficient of friction will be 0.587

6 0
3 years ago
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