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-BARSIC- [3]
4 years ago
5

Numerous engineering and scientific applications require finding solutions to a set of equations. Ex: 8x + 7y = 38 and 3x - 5y =

-1 have a solution x = 3, y = 2. Given integer coefficients of two linear equations with variables x and y, use brute force to find an integer solution for x and y in the range -10 to 10.
Physics
2 answers:
Irina-Kira [14]4 years ago
6 0

Answer:

we do not have the integer coeficients, so the solutions may not be in the range -10 to 10 (it does not happen for all coeficients) so let's do other thing:

Ok, suppose you have the equations:

1) A*x + B*y = C

2) a*x + b*y = c

where A, B, C, a, b and d are knowed.

Let's solve them in the most general way, and you always can use those solutions in the future, just need to replace the values of the constants up there.

First, we isolate x or y in a equation, let's do it with x in equation 1:

A*x  = C - B*y

x = (C - B*y)/A

Now we can replace this in the equation 2, and solve it for y:

a*x + b*y = c

a*(C - B*y)/A + b*y = c

y*(b - a*B/A) = c - a*C/A

y = (c - a*C/A)/(b - a*B/A)

Now you have a solution for y, and we you know the value of y, you can put it in the eqution:

x = (C - B*y)/A

and find the value of x

mote1985 [20]4 years ago
5 0
Need help with this too
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3 years ago
3 A jet plane accelerated along a straight runway from rest to a
aleksklad [387]

Explanation:

v=140 m/s

t=50s

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for acceleration:

from Newton's first law of motion:

v=u+at

140=0+a50

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Mkey [24]

Answer:

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Explanation:

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3 years ago
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3 years ago
Read 2 more answers
Determine the speed of sound in air at 300 K. Also determine the Mach number of an aircraft moving in the air at a velocity of 3
amm1812

Answer:

c_3_0_0_K=347.19m/s

M=0.864

Explanation:

The speed of sound in the air increases 0.6 m / s for every 1 ° C increase in temperature.  An approximate speed can be calculated using the following empirical formula:

c=331.5+0.6\vartheta

Where:

\vartheta=T-273.15K\\\\

A more exact equation, usually referred to as adiabatic velocity of sound, is given by the following formula:

c=\sqrt{k*R*T}

Where:

R= Gas\hspace{3}constant\hspace{3}of\hspace{3}air=0.287kJ/kg*K=287J/kg*K\\k=Specific\hspace{3}heat\hspace{3}ratio=1.4\\T=Temperature=300K

Hence:

c=\sqrt{(287)*(1.4)*(300)} =347.1887095\approx347.19m/s

Now, the Mach number at which an aircraft is flying can be calculated by:

M=\frac{u}{c}

Where:

u= Velocity\hspace{3}of\hspace{3}the\hspace{3}moving\hspace{3}aircraft\\c= Speed\hspace{3}of\hspace{3}sound\hspace{3}at\hspace{3}the\hspace{3}given \hspace{3}altitude

Therefore:

M=\frac{300}{347.19} =0.8640833984\approx0.864

5 0
4 years ago
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