20600Cal               
Explanation:
Given parameters: 
Mass of water = 319.5g
Initial temperature = 35.7°C
Final temperature = 100°C
Unknown: 
Calories needed to heat the water = ? 
Solution: 
The calories is the amount of heat added to the water. This can be determined using;
      H  =   m  c Ф
 c  = specific heat capacity of water = 4.186J/g°C 
    H is the amount of heat 
     Ф is the change in temperature
     H = m c (Ф₂ - Ф₁) 
     H = 319.5 x 4.186 x (100 - 35.7) = 85996.56J
Now; 
      1kilocalorie = 4184J
       
85996.56J to kCal;  = 20.6kCal  = 20600Cal
   = 20.6kCal  = 20600Cal
                 
learn more: 
Specific heat brainly.com/question/3032746
#learnwithBrainly
 
        
             
        
        
        
false,
sodium has a vigorous reaction with water.
This can be observed by putting a piece of sodium in water,
it moves swiftly across the surface of water and reacts violently.
 
        
             
        
        
        
Answer:
This is because no energy is being created or destroyed in this system
Explanation:
I think this is correct? I hope it helps.        
 
        
                    
             
        
        
        
Aluminum has three oxidation states. The most common one is +3. The other two are +1 and +2. One +3 oxidation state for Aluminum can be found in the compound aluminum oxide, Al2O3.