The first sail was developed in 1300 BC in Mesopotamia
We know that the acceleration due to gravity g is: g =
9.81 m/s^2
So the centripetal acceleration (w) is:
w^2 = 1.5 g / r
w^2 = 1.5 * (9.81 m/s^2) / 5 m
w = 1.716 rad / s
To convert to rad to rev:
w = (1.716 rad / s) * (1 rev / 2π rad) * (60 s/min)
<span>w = 16.4 rev/min </span>
Answer:
Explanation:
Let the bigger crate be in touch with the ground which is friction less. In the first case both m₁ and m₂ will move with common acceleration because m₁ is not sliding over m₂.
1 ) Common acceleration a = force / total mass
= 234 / ( 25 +91 )
= 2.017 m s⁻².
2 ) Force on m₁ accelerating it , which is nothing but friction force on it by m₂
= mass x acceleration
= 25 x 2.017
= 50.425 N
The same force will be applied by m₁ on m₂ as friction force which will act in opposite direction.
3 ) Maximum friction force that is possible between m₁ and m₂
= μ_s m₁g
= .79 x 25 x 9.8
= 193.55 N
Acceleration of m₁
= 193 .55 / 25
= 7.742 m s⁻²
This is the common acceleration in case of maximum tension required
So tension in rope
= ( 25 +91 ) x 7.742
= 898 N
4 ) In case of upper crate sliding on m₂ , maximum friction force on m₁
= μ_k m₁g
= .62 x 25 x 9.8
= 151.9 N
Acceleration of m₁
= 151.9 / 25
= 6.076 m s⁻².
Answer:
98.1 Joule
Explanation:
Solution,
⇒Mass(m)=10kg
⇒Weight(F)=Mg=10×9.81=98.1N
⇒Distance(d)=1m
Now,
Work done=F×d
=98.1×1
=98.1J
