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Ket [755]
3 years ago
9

A student places blocks on a 100cm long see-saw as shown/

Physics
1 answer:
Hunter-Best [27]3 years ago
8 0

Answer:

Part 1)

\tau_1 = 5 \times (0.50) = 2.5 N m

Part 2)

\tau_2 = 14 \times (0.30) = 4.2 N m

Part 3)

\tau_3 = 1.4 N m

Part 4)

Since torque on right side is more so here it will turn and slip over it

Explanation:

As we know that the block A is placed at distance

d = 50 cm from the hinge at 70 cm mark

So torque due to weight of A is given as

\tau_1 = 5 \times (0.50) = 2.5 N m

the block B is placed at distance

d = 30 cm from the hinge at 70 cm mark

So torque due to weight of B is given as

\tau_2 = 14 \times (0.30) = 4.2 N m

Now torque due to weight of the scale is given as

\tau_3 = 7(0.20)

\tau_3 = 1.4 N m

now torque on left side of scale is given as

\tau_{left} = \tau_1 + \tau_3

\tau_{left} = 2.5 + 1.4 = 3.9 N m

Torque on right Side is given as

\tau_{right} = \tau_2 = 4.2 Nm

Since torque on right side is more so here it will turn and slip over it

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The mass of a body:
IRINA_888 [86]

Answer:

the mass of body increases when accelerated.

7 0
3 years ago
Read 2 more answers
What is pressure? A)Shown in picture B)Shown in picture C)Shown in picture D)Shown in picture
mr Goodwill [35]

Answer:

The force exerted on a given area.

Option B is the right option.

Explanation:

<h2><u>About</u><u> </u><u>pressure</u></h2>

Pressure is defined as force acting per unit area. It's SI unit is Pascal or N/m^2.

Formula to find pressure is:

\frac{thrust(f)}{area(a)}

The force acting perpendicular on a surface is called the <u>thrust</u><u>.</u> It is a vector quantity.

<u>One </u><u>Pascal </u><u>pressure</u>

One Pascal pressure is defined as the pressure exerted in a surface of area m^2 by the thrust of 1 N

Hope this helps ..

Good luck on your assignment.....

6 0
3 years ago
A 1200 kg car traveling north at 10 m/s is rear-ended by a 2000 kg truck traveling at 30 m/s. What is the total momentum before
tino4ka555 [31]

Answer:

The total momentum before and after collision is 72000 kg-m/s.

Explanation:

Given that,

Mass of car = 1200 kg

Velocity of car = 10 m/s

Mass of truck = 2000 kg

Velocity of truck = 30 m/s

Using conservation of momentum

The total momentum before the collision is equal to the total momentum after collision.

m_{1}v_{1}+m_{2}v_{2}=(m_{1}+m_{2})V

Where, m_{1}=mass of car

v_{1} =velocity of car

m_{1}=mass of truck

v_{1} =velocity of truck

Put the value into the formula

1200\times10+2000\times30=(1200+2000)V

V=\dfrac{1200\times10+2000\times30}{(1200+2000)}

V = 22.5\ m/s

Now, The total momentum before collision is

P=m_{1}v_{1}+m_{2}v_{2}

P=1200\times10+2000\times30

P=72000\ kg-m/s

The total momentum after collision is

P=(m_{1}+m_{2})v_{2}

P=(1200+2000)\times22.5

P= 72000 kg-m/s

Hence, The total momentum before and after collision is 72000 kg-m/s.

4 0
3 years ago
1.
Shalnov [3]

Answer:

No.

Explanation:

Given the following :

Velocity (V) of ball = 5m/s

Radius = 1m

Can the ball reach the highest point of the circular track

of radius 1.0 m?

The highest point in the track could be considered as the diameter of the circle :

Radius = diameter / 2;

Diameter = (2 * Radius) = (2*1) = 2

Maximum height which the ball can reach :

Using the relation :

Kinetic Energy = Potential Energy

0.5mv^2 = mgh

0.5v^2 = gh

0.5(5^2) = 9.8h

0.5 * 25 = 9.8h

12.5 = 9.8h

h = 12.5 / 9.8

h = 1.2755

h = 1.26m

Therefore maximum height which can be reached is 1.26m.

Since h < Diameter

7 0
4 years ago
imagine a horse pulling a cart. What would happen to the speed of the cart if several bags of cement were adding to the cart?
iogann1982 [59]
Assuming the power delivered by the horse does not change, the speed of the cart will decrease.
In fact, the power delivered by the horse is the work done by the horse (W) per unit time (t):
P=\frac{W}{t}
<span>If several bags are added to the cart, the horse must do more work to transport them. Therefore, W in the fraction increases. But if the power P of the horse is constant, then it means that the time t must increase as well. So, the horse will take more time to transport the car, and this means that the speed of the cart has decreased.</span>
7 0
3 years ago
Read 2 more answers
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