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QveST [7]
3 years ago
9

What is the y-intercept for the following table?

Mathematics
2 answers:
ser-zykov [4K]3 years ago
5 0
The first number for the Y it gives on the chart is the intercept
So 3 is correct
Hope that helped:D
Serhud [2]3 years ago
5 0
Y-intercept when x=0 so the correct answer y=3 is intercept
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Write an equation of a rational function that has a hole at 3, a vertical asymptote at -4 and a horizontal asymptote at 2
Sauron [17]
F(x)=2x(x-3)/(x+4)(x+3), Creation of the hole: have 3 as a solution for both numerator and denomenator 
                                     Formation of a vertical asymptote at -4: have the denominator equal to zero when plugging in -4 such that the denominator equals to zero, 
                                     horizontal asymptote: have the highest degree of numerator and denominator equal and the quotient of their coefficient equal to 2(ever wonder why there is an "x" in the numerator? It is to set the highest degree of the numerator and denominator equal to each other.
                     If you need more explanations, ask, glad to help.

6 0
3 years ago
Please help me i have been trying this for so long.
andre [41]

Answer:

The value of a is 101°, b is 79°, c is 83° and d is 97°

7 0
3 years ago
There are 10 marbles in a bag, and the marbles are either red or blue. Eric will randomly choose two marbles from the bag, witho
Vilka [71]
Number of red marbles in bag = r.  b = 10-rProbability of first marble being red: r/10Second marble being red: (r-1)/9total probability = 2/15 = (r-1)*r/90r = 4b = 6
4 0
3 years ago
Read 2 more answers
Help picture below problem 16
Allisa [31]

Answer:

5

Step-by-step explanation:

a²+b²=c²

In this case c is 13 and b is 12

a²+12²=13³

a²+144=169

Subtract 169 and 144 to find a

169-144=25

The square root of 25 is 5

5 0
3 years ago
Find all solutions to the equation in the interval [0, 2π). cos 2x - cos x = 0
Jlenok [28]
This is the concept of algebra, to solve the expression we proceed as follows;
cos 2x-cosx=0
cos 2x=cosx
but:
cos 2x+1=2(cos^2x)
thereore;
from:
cos 2x=cos x
adding 1 on both sides we get:
cos 2x+1=cos x+1
2(cos^2x)=cosx+1
suppose;
cos x=a
thus;
2a^2=a+1
a^2-1/2a-1/2=0
solving the above quadratic we get:
a=-0.5 and a=1
when a=-0.5
cosx=-0.5
x=120=2/3π
when x=1
cos x=1
x=0
the answer is:
x=0 or x=2/3π

4 0
3 years ago
Read 2 more answers
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