Ookay
1) T
2) T
3) F
Hope i helped :)
For this problem, we use the Beer Lambert's Law. Its usual equation is:
A = ∈LC
where
A is the absorbance
∈ is the molar absorptivity
L is the path length
C is the concentration of the sample solution
As you notice, we only have to find the absorbance. But since we are not given with the molar absorptivity, we will have to use the modified equation that relates % transmittance to absorbance:
A = 2 - log(%T)
A = 2 - log(27.3)
A = 0.5638
look at the atomic number using the periodic table. The Atomic number equals the amount of protons and the amount of protons equals the amount of electrons
Answer:
The phenotypic percentage of having yellow or green seeds is 50% for having either of the two colours
Explanation:
The crossing to determine the offsprings is shown in the image attached where we have two green (Yy) seeds and two yellow (yy) seeds as offsprings.
Thus, <u>the phenotypic percentage of having yellow or green seeds is 50% for having either of the two colours</u>.
Note, the dominant allele is "Y" while the recessive allele is "y". Thus, Yy would produce a yellow colour while yy would produce a green colour (as both mentioned in the question).
Also note that phenotype describes the outward properties/characteristics of an individual.
Answer: 23 g
Explanation:
Amountafter = Amountbefore * (1/2)^(t/thalf)
Amountafter = (750 grams) * (1/2)^(62.0 hours/12.4 hours)
Amountafter = 23.4375 grams
750 has 2 significant digits
12.4 and 62.0 have 3 significant digits
So we take the lower of 2 significant digits:
23 grams
