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Amanda [17]
3 years ago
11

Consider two regions of space containing a static electric field, region A and region B. In region A the equipotential lines are

more closely spaced than those in region B. What can be said about the relative strength of the electric field in the two regions
Physics
1 answer:
STALIN [3.7K]3 years ago
7 0

Answer:

The electric field of region A is stronger than the electric field of region B.

Explanation:

The expression for the electric field at a point is define by the formula,

E=\frac{kq}{r^{2} }

Here, r is the distance between the two charges.

Therefore,

E\alpha \frac{1}{r^{2} }

Here, electric field is inversely proportional to the square of the distance between the two charges.

Hence, smaller the distance between the charges, more will be the electric field.

According to the given situation, two regions A and B containing a static electric field, in region A the equipotential lines are closely bound than the region B.

Therefore electric field of region A is stronger than the electric field of region B.

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Scorpion4ik [409]

Answer:

SKID

Explanation:

In general, airplane tracks are flat, they do not have cant, consequently the friction force is what keeps the bicycle in the circle.

Let's use Newton's second law, let's set a reference frame with the horizontal x-axis and the vertical y-axis.

Y axis y

     N- W = 0

     N = W

X axis (radial)

        fr = m a

the acceleration in the curve is centripetal

         a = \frac{v^2}{r}

the friction force has the expression

        fr = μ N

we substitute

       μ mg = m v²/r

       v = \sqrt{\mu g r}

we calculate

      v = \sqrt{0.1 \ 9.8 \ 3}

      v = 1,715 m / s

to compare with the cyclist's speed let's reduce to the SI system

        v₀ = 18 km / h (1000 m / 1 km) (1 h / 3600 s) = 5 m / s

We can see that the speed that the cyclist is carrying is greater than the speed that the curve can take, therefore the cyclist will SKID

5 0
3 years ago
When did agriculture first began?​
timofeeve [1]

Answer:

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5 0
3 years ago
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1. A cyclist accelerates from 0 m/s to 9 m/s in 3 seconds. What is his<br>acceleration?​
Lapatulllka [165]

The cyclist accelerates from 0 m/s to 9 m/s in 3 seconds with an acceleration of 3 m/s².

Answer:

Explanation:

Acceleration exerted by an object is the measure of change in speed or velocity of that object with respect to time. So the initial and final velocities play a major role in determining the acceleration of the cyclist. As here the initial velocity of the cyclist is the speed at rest and that is given as 0 m/s. Then after 3 seconds, the velocity of the cyclist changes to 9 m/s.

Then acceleration = change in velocity/Time.

Acceleration = \frac{Change in velocity}{Time taken}

Acceleration = (9-0)/3=9/3=3 m/s².

So the cyclist accelerates from 0 m/s to 9 m/s in 3 seconds with an acceleration of 3 m/s².

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3 years ago
Which BMI standard for teens is considered under weight?
Lena [83]
First let’s pick one at random

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