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3 years ago

Need help! What is true about the relationship among wavelength, frequency, and energy in electromagnetic radiation?

Physics

2 answers:

lesantik [10]3 years ago

7 0

I believe the answer is D

postnew [5]3 years ago

4 0

The answer is D I just took the test

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A magnetic field with the same orientation as the Earth's field is said to

Alex73 [517]

Answer: Normal polarity

Explanation:

Magnetic field in line with the earth field is said to have polarity.

If the magnetic field is in opposite direction with the earth's field, then, the polarity is said to be a reversed polarity.

But since the magnetic field is with the same orientation as the Earth's field, it is said to have normal polarity.

6 0

3 years ago

If you can walk 3 miles per hour, how much is that in meters per second?

deff fn [24]

To convert 3 miles per hour into m/s, first we have to convert miles in to meter and then hour in to second.

As $1 miles = 1.609344 km = 1.609344\times 10^3 m = 1609.3 m$ and $1 hour=60 minutes = 60\times 60= 3600s$

Therefore,

$3 miles/ h=\frac{3\times1609.3m}{3600s} =1.34 m/s$

4 0

3 years ago

Creating a prototype and troubleshooting are steps in the development of?

balu736 [363]

Your answer is a new experiment, since it's something that hasn't been tried before, or has, but resulted in with lots of errors.

8 0

3 years ago

Read 2 more answers

A plastic light pipe has an index of refraction of 1.48. For total internal reflection, what is the minimum angle of incidence i

Rama09 [41]

Answer:

a) 42.52°

b) 63.98°

Explanation:

Refractive index of pipe = 1.48 = n₂

Refractive index of air = 1.0003 = n₁

$\theta_r=sin^{-1}\frac{n_1}{n_2}\\\Rightarrow \theta_r=sin^{-1}\frac{1.0003}{1.48}\\\Rightarrow \theta_r=sin^{-1}0.676\\\Rightarrow \theta_r=42.52^{\circ}$

∴ Minimum angle of incidence is 42.52°

Refractive index of water = 1.33 = n₁

$\theta_r=sin^{-1}\frac{n_1}{n_2}\\\Rightarrow \theta_r=sin^{-1}\frac{1.33}{1.48}\\\Rightarrow \theta_r=sin^{-1}0.899\\\Rightarrow \theta_r=63.98^{\circ}$

∴ Minimum angle of incidence is 63.98°

5 0

4 years ago

A rocket takes off from Earth's surface, accelerating straight up at 47.2 m/s2. Calculate the normal force (in N) acting on an a

lions [1.4K]

Answer:

Approximately $4.61\times 10^{3}\; {\rm N}$ upwards (assuming that $g = 9.81\; {\rm m\cdot s^{-2}}$ .)

Explanation:

External forces on this astronaut:

Weight (gravitational attraction) from the earth (downwards,) and
Normal force from the floor (upwards.)

Let $(\text{normal force})$ denote the magnitude of the normal force on this astronaut from the floor. Since the direction of the normal force is opposite to the direction of the gravitational attraction, the magnitude of the net force on this astronaut would be:

$\begin{aligned}(\text{net force}) &= (\text{normal force}) - (\text{weight})\end{aligned}$ .

Let $m$ denote the mass of this astronaut. The magnitude of the gravitational attraction on this astronaut would be $(\text{weight}) = m\, g$ .

Let $a$ denote the acceleration of this astronaut. The magnitude of the net force on this astronaut would be $(\text{net force}) = m\, a$ .

Rearrange $\begin{aligned}(\text{net force}) &= (\text{normal force}) - (\text{weight})\end{aligned}$ to obtain an expression for the magnitude of the normal force on this astronaut:

$\begin{aligned}(\text{normal force}) &= (\text{net force}) + (\text{weight}) \\ &= m\, a + m\, g \\ &= m\, (a + g) \\ &= 80.9\; {\rm kg} \times (47.2\; {\rm m\cdot s^{-2}} + 9.81\; {\rm m\cdot s^{-2}}) \\ &\approx 4.61 \times 10^{3}\; {\rm N}\end{aligned}$ .

3 0

2 years ago