Answer:
L/2.
Explanation:
Hola.
En este caso, dado que el hombre empuja el cilindro desde el punto L=0 y hasta la mitad de la longitud entre el hombre y el cilindro, es claro que el cilindro se desplaza un L/2 más de la distancia inicial entre el hombre y el cilindro, de este modo, inferimos que el hombre también ha caminado L/2.
¡Saludos!
A. C = 75μF and B. V = 10V.
We have to use the equation k = C/C₀ and k = V₀/V which both are the dielectric constant.
A. The capacitance after the slab is inserted.
With C₀ = 15μF and k = 5.0. Clear k for the equation k = C/C₀:
C = k*C₀
C = (5.0)(15x10⁻⁶F) = 0.000075F
C = 75μF
B. The voltage across the capacitor's plates after the slab is inserted.
With V₀ = 50V and k = 5.0. Clear V from the equation k = V₀/V:
V = V₀/k
V = 50V/5.0
V = 10V
Answer:
Approximately 
(given that the magnitude of this charge is 
.)
Explanation:
If a charge of magnitude 
is placed in an electric field of magnitude 
, the magnitude of the electrostatic force on that charge would be 
.
The magnitude of this charge is 
. Apply the unit conversion 
:
.
An electric field of magnitude 
would exert on this charge a force with a magnitude of:
.
Note that the electric charge in this question is negative. Hence, electrostatic force on this charge would be opposite in direction to the the electric field. Since the electric field points due south, the electrostatic force on this charge would point due north.
V = at + V0
where v0 is the initial speed, a is the acceleration and t is the time.
So:
v = 5m/s^2*5s + 25m/s = 50 m/s
Is there a question in here somewhere?
