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3 years ago

8

I need help in this question I do t get it

2 answers:

lara31 [8.8K]3 years ago

8 0

The system won't have a unique solution when what appears to be two lines is really only one line. The coefficients in an equation for a line only matter in ratio; if we multiply them all by the same non-zero scalar we'll still have the same line, of course with an infinite number of points on it, our infinite number of solutions.

2x - y = 8

6x - 3y = 4a

We need these to be the same equation, meaning they have to have all the same solutions. So we have to figure out the factor to multiply the first equation by to get the second.

That factor is obviously 3 because 3(2x)=6x and 3(-y)=-3y. So we need the constants in the same ratio,

3(8) = 4a

24 = 4a

a = 6

Answer: B. 6

trasher [3.6K]3 years ago

5 0

Answer:

C

Step-by-step explanation:

<u>1.2*8=16</u>

<u>16-8=8</u>

<u>2.6*8=48</u>

<u>3*8=24</u>

<u>4*8=32</u>

<u>48-24=32</u>

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5√24

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3 years ago

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Timothy made 60 quarts of cider he poured the cider into containers. Each container holds 4/11 of a quart. How many containers d

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3 years ago

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A bird travels 200 meters in 50 seconds. What is its average speed?

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3 years ago

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At the beginning of each of her four years in college, Miranda took out a new Stafford loan. Each loan had a principal of $5,500

kaheart [24]

Answer:

D. $31,337.27

Step-by-step explanation:

We have that the initial amount of the loan is $5500.

Miranda took the loan for 4 years. So, the total present value is $5500×4 = $22,000.

The rate of interest on the loan is 7.5% i.e. 0.075 and it was for the duration of 10 years.

Also, it is given that the loan was compounded annually.

We have the formula as,

$P=\frac{\frac{r}{n}\times PV}{1-(1+\frac{r}{n})^{-t\times n}}$

i.e. $PV=\frac{P\times [1-(1+\frac{r}{n})^{-t\times n}]}{\frac{r}{n}}$

Substituting the values, we get,

i.e. $PV=\frac{P\times [1-(1+\frac{0.075}{12})^{-10\times 12}]}{\frac{0.075}{12}}$

i.e. $22000=\frac{P\times [1-(1+0.00625)^{-120}]}{0.00625}$

i.e. $22000=\frac{P\times [1-(1.00625)^{-120}]}{0.00625}$

i.e. $22000=\frac{P\times [1-0.4735]}{0.00625}$

i.e. $22000=\frac{P\times 0.5265}{0.00625}$

i.e. $P=\frac{22000\times 0.00625}{0.5265}$

i.e. $P=\frac{137.5}{0.5265}$

i.e. $P=261.16$

Thus, the total lifetime cost to pay of the loans compounded annually = 261.16 × 120 = $31,339.2

Hence, the total cost close to the answer is $31,337.27

7 0

3 years ago

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