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Dahasolnce [82]
3 years ago
6

How many grams of sodium sulfide can be produced when 45.3 g Na react with 105 g S?

Chemistry
1 answer:
RoseWind [281]3 years ago
8 0
The chemical reaction would be as follows:

<span>2Na + S → Na2S

We are given the amount of the reactants to be used in the reaction. We use these to calculate the amount of product. We do as follows:

45.3 g Na ( 1 mol / 22.99 g ) = 1.97 mol Na
105 g S ( 1 mol / 32.06 g ) = 3.28 mol S

The limiting reactant would be Na. We calculate as follows:

1.97 mol Na ( 1 mol Na2S / 2 mol Na ) (78.04 g / mol ) = 76.87 g Na2S produced</span>
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Answer:

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Xn = 167.99

By calculating in same process given above we get

r=0.995

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