I think this is AWESOME, but I think the last sentence of your conclusion is a bit off. <span> "If someone has an allergy to oil then they can still eat cake because applesauce makes an amazing substitute for oil." I think that you should say "This recipe is great for those who cannot eat/drink oil, the applesauce is an amazing substitute for oil."
I hope I helped! -Wajiha</span>
Answer:
The minimum time to reach the target is 2156s
Explanation:
Check attachment
Answer:
The magnitude of the acceleration is 
The direction is
north of east
Explanation:
From the question we are told that
The force exerted by the wind is 
The force exerted by water is 
The mass of the boat(+ crew) is
Now Force is mathematically represented as

Now the acceleration towards the north is mathematically represented as

substituting values


Now the acceleration towards the east is mathematically represented as

substituting values


The resultant acceleration is

substituting values


The direction with reference from the north is evaluated as
Apply SOHCAHTOA

![\theta = tan ^{-1} [\frac{a_e}{a_n } ]](https://tex.z-dn.net/?f=%5Ctheta%20%3D%20tan%20%5E%7B-1%7D%20%5B%5Cfrac%7Ba_e%7D%7Ba_n%20%7D%20%5D)
substituting values
![\theta = tan ^{-1} [\frac{0.808}{1.269 } ]](https://tex.z-dn.net/?f=%5Ctheta%20%3D%20tan%20%5E%7B-1%7D%20%5B%5Cfrac%7B0.808%7D%7B1.269%20%7D%20%5D)
![\theta = tan ^{-1} [0.636 ]](https://tex.z-dn.net/?f=%5Ctheta%20%3D%20tan%20%5E%7B-1%7D%20%5B0.636%20%5D)

X- points away from the charge
y- points in the direction of the force on the positive charge
z- points toward the charge
200 N, that is if the force is balanced and the wall doesn't move