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3 years ago

. A 5 kg turkey and a 3.5 kg turkey are suspended on opposite sides of a single pulley.

Physics

1 answer:

zavuch27 [327]3 years ago

6 0

Answer:

a) 40.3725 N

b) $a=1.729 m/s^2$

Explanation:

mass of turkey 1 M= 5 kg

mass of turkey 2 m= 3.5 kg

Let T be the tension in the string and a be the acceleration of the system

then from FBD in the attachment

T-mg=ma.................1

Mg-T=Ma..................2

from 1 and 2 we find a as

$a= \frac{Mg-mg}{M+m}$

now substituting the values we get

$a= \frac{5g-3.5g}{5+3.5}$

$a= \frac{1.5g}{8.5}$

$a=1.729 m/s^2$

now from equation 1 we can calculate Tension T as

T-mg=ma

T= m(a+g)

T= 3.5(1.729+9.81)= 40.3725 N

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A 190 g air-track glider is attached to a spring. The glider is pushed in 8.6 cm against the spring, then released. A student wi

spin [16.1K]

Answer:

The spring constant = 9.25 N/m

Explanation:

The equation of an object attached to a spring that is oscillating is

T = 2π√(m/k)

Where T = period of the oscillation, m = mass of the object, k = spring constant.

Making k the subject of the equation,

k = 4π²m/T²......................... Equation 1

Note: Period(T) is the time taken to complete one oscillation

Given: T = t/10 = 9.0/10 = 0.9 s, m = 190 g = 0.19 kg.

Constant: π = 3.14

Substitute these values into equation 1.

k = 4(3.14)²(0.19)/0.9²

k = 7.4933/0.81

k = 9.25 N/m

Thus the spring constant = 9.25 N/m

5 0

3 years ago

Two loudspeakers (A and B) are 3.20m apart and emitting a sound with a frequency of 400Hz. An observer is 2.10m directly in fron

TiliK225 [7]

Answer:

The observer hears a loud sound

Explanation:

In order to know if the observer hears a loud or a quiet sound, you need to know if there is a constructive or destructive interference between the sound waves of the loudspeakers.

You first calculate the distance between the observer and the loudspeakers.

The distances are given by:

d1: distance to loudspeaker A = 2.10m

d2: distance to loudspeaker B

$d_2=\sqrt{(3.20m)^2+(2.10m)^2}=3.827m$

Next, you calculate the wavelength of the sound waves by using the following formula:

$\lambda=\frac{v_s}{f}$

vs: speed of sound = 343 m/s

f: frequency of the waves = 400Hz

λ: wavelength

$\lambda=\frac{343m/s}{400Hz}=0.8575m$

Next, you calculate the path difference between the distance from the observer to the loudspeakers:

$\Delta d=3.827m-2.10m=1.727m$

You obtain a constructive interference (loud sound) if the quotient between the wavelength of the sound and the difference path is an integer:

$\frac{\Delta d}{\lambda}=\frac{1.727m}{0.857}\approx2$

Then, there will be a constructive interference, and the sound who the observer hears is loud.

5 0

3 years ago

A solid ball and a hollow ball, each with a mass of 1.00 kg and radius of 0.100 m start from rest and roll down a ramp of length

nordsb [41]

Answer:

The solid ball and hollow ball both will reach the bottom with the same speed.

Explanation:

The speed of the solid and hollow balls is independent of the mass and the radius. A solid and hollow ball experience same speed on a given incline.

The speed can be calculated as

v = √(10/7)gh

where g is gravitational acceleration and h is the height

sinθ = h/L

h = L*sinθ

h = 3*sin(35)

h = 1.72 m

v = √(10/7)*9.8*1.72

v = 4.91 m/s

Both balls will reach the bottom at the speed of 4.91 m/s.

8 0

3 years ago

List the three ways in which water reaches the atmosphere

frozen [14]

Water cycle, evaporation, condensation, and freezing

7 0

3 years ago

The magnitude of the electrostatic force between two identical ions that are separated by a distance of 5.0A is 3.7×10^-9N.a) wh

jeyben [28]

Explanation:

Given that,

Electrostatic force, $F=3.7\times 10^{-9}\ N$

Distance, $r=5\ A=5\times 10^{-10}\ m$

(a) $F=\dfrac{kq^2}{r^2}$ , q is the charge on the ion

$q=\sqrt{\dfrac{Fr^2}{k}}$

$q=\sqrt{\dfrac{3.7\times 10^{-9}\times (5\times 10^{-10})^2}{9\times 10^9}}$

$q=3.2\times 10^{-19}\ C$

(b) Let n is the number of electrons are missing from each ion. It can be calculated as :

$n=\dfrac{q}{e}$

$n=\dfrac{3.2\times 10^{-19}}{1.6\times 10^{-19}}$

n = 2

Hence, this is the required solution.

8 0

3 years ago