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Shalnov [3]
3 years ago
10

Allison wants to determine the density of a bouncing ball. which metric measurements must she use?

Physics
1 answer:
lubasha [3.4K]3 years ago
3 0
Density depends on mass and volume so option D is correct answer. Hope this helps!
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What scenario would most likely lead to a higher level of physical fitness among people who live in a city?
ExtremeBDS [4]
More people walk to school or work hope this helps
7 0
3 years ago
HEEELLLPPPP MMEEEEEEEE! please​
Elena-2011 [213]

Answer:

it is c

Explanation:

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3 0
3 years ago
A p-wave arrives at 3:00:00 and the s-wave arrives at 3:07:20, what is the exact distance that the seismic station is away from
maxonik [38]

The exact distance from the seismic station to the epicenter is 6000 km.

<h3>Epicenter of earthquake</h3>

The earthquake's epicenter is the point above the fault location on the earth's surface.

Given that:

A p-wave arrives at 3:00:00 and the s-wave arrives at 3:07:20.

Difference in arrival time = 3:07:20 - 3:00:00 = 7 minutes 20 seconds

From the earthquake time travel graph, a time difference of 7 min 20 sec is at x = 6

The exact distance from the seismic station to the epicenter is 6000 km.

Find out more on Epicenter of earthquake at: brainly.com/question/1969968

4 0
2 years ago
The pressure and absolute temperature of an ideal gas are both tripled, the volume is __________. not changed
ankoles [38]

Answer:

Not Changed

Explanation:

To know what happened with the volume you need to know the Ideal gas Law

\frac{P_{1}V_{1}}{T1} =\frac{P_{2}V_{2} }{T2}

This law is a combination of the other four laws: Boyles's, Charles's, Avogadro's, and Guy-Lussac's.

The initial state is represented by P1, V1, T1 and the final by P2, V2, T2.

In this case:

T_{2} =3T_{1} \\P_{2} =3P_{1}

Replacing on the equation

\frac{P_{1}V_{1}}{T1} =\frac{3P_{1}V_{2}}{3T_{1} }

If we clear from the equation V2

\frac{P_{1}V_{1}3T_{1}}{T_{1} 3P_{1}} ={V_{2}}

Then cancel both P1 and T1

\frac{3V_{1}}{3} =V_{2}

You will found that

V_{1} =V_{2}

3 0
3 years ago
What is the energy (in joules) and the wavelength (in meters) of the line in the spectrum of hydrogen that represents the moveme
soldi70 [24.7K]

Answer:

The energy is 4.57x10^{-19} J and the wavelength is 4.34x10^{-7}m for the line in the spectrum of hydrogen that represents the movement of an electron from Bohr orbit with n = 2 to the orbit with n = 5.

<em>In what part of the electromagnetic spectrum do we find this radiation? </em>

In the Ultraviolet part of the electromagnetic spectrum.

Explanation:

The energy of the absorbed photon can be known by the difference in energy between the two states in which the transition is happening (In this case from n = 2 to n = 5):

E = E_{upper}-E_{lower}   (1)

The permitted energy for the atom of hydrogen, according with the Bohr's model, is defined as:

E_{n} = -\frac{13.606 eV}{n^{2}}   (2)

Or it can be expressed in Joules, since 1eV = 1.60x10^{-19}J

E_{n} = -\frac{2.18x10^{-18} J}{n^{2}}   (3)

Where the value -2.18x10^{-18} represents the energy of the ground state¹ and n is the principal quantum number.

For the case of n = 2:

E_{2} = -\frac{2.18x10^{-18} J}{(2)^{2}}

E_{2} = -5.45x10^{-19} J

For the case of n = 5:

E_{5} = -\frac{2.18x10^{-18} J}{(5)^{2}}

E_{5} = -8.72x10^{-20} J

Replacing those values in equation (1) it is gotten:

E = -8.72x10^{-20} J-(-5.45x10^{-19} J )

E = 4.57x10^{-19} J

The wavelength can be determined by means of the Rydberg formula:

\frac{1}{\lambda} = R(\frac{1}{n_{l}^{2}}-\frac{1}{n_{u}^{2}})  (4)

Where R is the Rydberg constant, with a value of 1.097x10^{7}m^{-1}

For this particular case n_{l} = 2 and n_{u} = 5:

\frac{1}{\lambda} = 1.097x10^{7}m^{-1}(\frac{1}{(2)^{2}}-\frac{1}{(5)^{2}})

\frac{1}{\lambda} = 1.097x10^{7}m^{-1}(0.21)

\frac{1}{\lambda} = 2303700m^{-1}

\lambda = \frac{1}{2303700m^{-1}}

\lambda = 4.34x10^{-7}m

So the energy is 4.57x10^{-19} J and the wavelength is 4.34x10^{-7}m for the line in the spectrum of hydrogen that represents the movement of an electron from Bohr orbit with n = 2 to the orbit with n = 5.

<em>In what part of the electromagnetic spectrum do we find this radiation? </em>

In the Ultraviolet part of the electromagnetic spectrum.

Key terms:

¹Ground state: State of minimum energy.  

8 0
3 years ago
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