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Sonbull [250]
3 years ago
13

Any child is pushing a shopping cart at a speed of 1.5 m/s.how long will it take this child to push the cart down the aisle with

a length of 9.3m
Physics
1 answer:
NARA [144]3 years ago
7 0
1.5 m/s is the velocity. 9.3 m is the length of aisle, over which Distance will be covered. Time is demanded in which the child will move the cart over the aisle with 1.5 m/s. v=S/t and, t=S/v Put values, t=9.3/1.5=6.2 s
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What causes a objects to move or stay still? claim and evidence
jek_recluse [69]

Answer:

A force

Explanation:

A push or a pull is an example of a force and can cause an object to speed up, slow down, etc..  Newton's laws tell us that 1- an object will not change its motion unless a force acts on it 2- the force on an object is equal to its mass times its acceleration. 3- The third law states that for every action (force) in nature there is an equal and opposite reaction.. However, forces like gravity and friction can resist movement.

4 0
3 years ago
PLease Help !!! A.S.A.P!!! will be marked as brainlest !!!!! 16 points
White raven [17]

This one is correct

Jamie is correct, because the mechanical energy is converting to electrical energy.

3 0
3 years ago
Read 2 more answers
007 (part 1 of 2) 1.0 points
levacccp [35]

Answer:

a) The angle of refraction is approximately 34.7

b) The angle the light have to be incident to give an angle of refraction of 90° is approximately 53.42°

Explanation:

According to Snell's law, we have;

\dfrac{n_1}{n_2} = \dfrac{sin (\theta_2)}{sin (\theta_1)}

The refractive index of the glass, n₁ = 1.66

The angle of incident of the light as it moves into water, θ₁ = 27.2°

a) The refractive index of water, n₂ = 1.333

Let θ₂ represent the angle of refraction of the light in water

By plugging in the values of the variables in Snell's Law equation gives;

\dfrac{1.66}{1.333} = \dfrac{sin (\theta_2)}{sin (27.2^{\circ})}

sin (\theta_2) = sin (27.2^{\circ}) \times \dfrac{1.66}{1.333} \approx 0.5692292265

θ₂ = arcsin(0.5692292265) ≈ 34.7°

The angle of refraction of the light in water, θ₂ ≈ 34.7°

b) When the angle of refraction, θ₂ = 90°, we have;

\dfrac{1.66}{1.333} = \dfrac{sin (90^{\circ})}{sin (\theta_1)}

sin (\theta_1) = \dfrac{sin (90^{\circ})}{\left( \dfrac{1.66}{1.333}\right)} = sin (90^{\circ}) \times \dfrac{1.333}{1.66} \approx 0.803

θ₁ ≈ arcsin(0.803) ≈ 53.42°

The angle of incident, θ₁, that would give an angle of refraction of 90° is θ₁ ≈ 53.42°

3 0
3 years ago
Kim is cutting lengths of ribbon so that each length of ribbon equals 8 inches. How many centimeters does 8 inches equal
Aloiza [94]
I think it's 96 because 1 inch = 12 centimeters so 8 multiply by 12 is 96 yah its 96
7 0
4 years ago
A force of 48 newtons is required to start a 5.0 kg box moving across a horizontal concrete floor. What is the coefficient of st
Soloha48 [4]

1) The coefficient of static friction is 0.980

2) The coefficient of kinetic friction is 0.908

Explanation:

1)

In the first situation, the box is still at rest. There are two forces acting on the box:

- The force of push, F, forward

- The force of static friction, F_f

Since the box is in equilibrium we have

F_f = F (1)

The value of frictional force changes from zero to a maximum value which is given by:

F_f = \mu_s mg (2)

where

\mu_s is the coefficient of static friction

m is the mass of the box

g is the acceleration of gravity

So, if the force F needed to put the box in motion is 48 N, it means that this is also the maximum value of the force of friction. So, we can combine eq.(1) and (2) to find the coefficient of static friction:

\mu_s = \frac{F}{mg}

where:

F = 48 N

m = 5.0 kg

g=9.8 m/s^2

Substituting,

\mu_s = \frac{48}{(5.0)(9.8)}=0.980

2)

In this second situation, the object is already in motion, so the equation of motion is:

F-F_f = ma

where

F = 48 N is the force applied forward

a = 0.70 m/s^2 is the acceleration of the box

F_f = \mu_k mg is the force of kinetic friction, where

\mu_k is the coefficient of kinetic friction

We can therefore rearrange the equation to find the coefficient:

F-\mu_k mg = ma\\\mu_k mg = F-ma\\\mu_k = \frac{F-ma}{mg}=\frac{48-(5.0)(0.70)}{(5.0)(9.8)}=0.908

Learn more about friction:

brainly.com/question/6217246

brainly.com/question/5884009

brainly.com/question/3017271

brainly.com/question/2235246

#LearnwithBrainly

7 0
3 years ago
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