Answer:
The correct answer would be - observing with the help of five senses.
Explanation:
To find and describe the physical properties of the given substance or the solution or liquid students can observe using their five senses. By looking at the liquid one can find its state and color, by smelling students can find the odor of the sample, by touching it one can observe and describe the texture.
Fluidity can also be measure by the touch if the solution is viscous or free-floating. By using a thermometer and using a graduated cylinder one can find the temperature at room temperature and the weight of substance respectively.
Answer:
The density of the liquid in beaker B is less than the that of ice.
Explanation:
Ice will float if its mass is less than the mass of the liquid it displaces.
For example, the density of ice is less than that of water.
A 10 cm³ cube of ice has a mass of about 9 g, while the mass of 10 cm³ of water is 10 g. Thus, 9 g of ice displaces 10 g of water.
The denser water displaces the lighter ice and the ice floats to the top.
If the density of the liquid is <em>less than</em> that of water, say, 8 g/cm³, the ice will displace only 8 g of the liquid. The ice will sink.
The answer is A: fleas and cats.
Answer:
26 grams of D will be produced.
Explanation:
The reaction is given by:
A + B -----> C + D
Mass of A reacted = 21 g
Mass of B reacted = 22 g
Mass of C formed = 17 g
Mass of D formed = m =?
According to law of conservation of mass, the total mass of the reactants used is equal to the total mass of the product formed.
Then:
mass of A reacted + mass of B reacted = mass of C formed + mass of D formed
21 + 22 = 17 + m
m = 26 g
Answer:
A. The rate of heat transfer through the material would increase.
Explanation:
To calculate the heat transfer in a heat exchanger you decide that there is not heat leakage to the surroundings, that means that magnitude of the two transfer rates will be equal. Any heat lost by the hot fluid, is gained by the cold fluid. The equation that describes this is Q = m×Cp×dT
Where:
heat = mass flow ×specific heat capacity × temperature difference
So if we increase the rate of flow of cooling water and the other variables that ypu can control remain the same, the result is that the rate of heat transfer through the material would increase, as it is stated in option a.
