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3 years ago

6

Find concentration of each ions: 600.0 ml of solution containing 1.50 grams of Cr(NO3)2

1 answer:

worty [1.4K]3 years ago

4 0

400ml my dude is the wrong answer

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10. As the temperature of a fixed volume of a gas increases, the pressure will _______

vesna_86 [32]

The answer is Increase

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3 years ago

Clay and organic matter generally have higher capacity for retaining nutrients than silt and sand.

Svetlanka [38]

The answer is false because clay have more silt and sand

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3 years ago

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The compound IF5 contains Question 16 options: polar covalent bonds with partial negative charges on the F atoms. ionic bonds. p

larisa86 [58]

Answer:

See explanation

Explanation:

The molecule IF5 possesses five I-F polar bonds. However, the presence of polar bonds does not automatically imply that the molecule will be polar.

The geometry of the molecule is very important in determining the polarity of a compound. Since IF5 has a lone pair of electrons, the molecule is bent and as such there is a permanent dipole moment created in the molecule thereby making IF5 polar in nature.

6 0

3 years ago

How would you prepare 2.00 l of a 0.25 m acetate buffer at ph= 4.50 from concentrated acetic acid (17.4 m) and 1.00 m naoh? the

zvonat [6]

The reaction of acetic acid with sodium hydroxide is:

$CH_3COOH + NaOH CH_3COONa + H_2O$

The ratio of A-/HA is calculated as follows:

According to Henderson Hasslebach equation:

$[A-]/[HA] = 10^p^H^-^p^K^_a$

$= 10^4^.^7^6^-^4^.^5^ = ^2^.^1^8$

The total concentration of HA and A- = 2.0 L * 0.25 M = 0.5 mol.

$[ A- ]+ [ HA ]= 0.5$

$[ A^- ] = 0.5 – [ HA]$

[ HA] = 0.156 mol and [ A- ]= 0.343 mol

Total of 0.5 moles of acetic acid is required:

$0.5 mol HA * 60.0 g$

HA = 30.0 g acetic acid

Conversion of 0.343 moles of the acetic acid to acetate can be performed by adding NaOH

$0.343 mol HA * (1 mol NaOH/1 mol HA) * (1000 mL/1 mol NaOH)$

= 343 mL

Thus, 343 mL of 1M NaOH is required

3 0

3 years ago

What is the delta H fusion used to calculate volume of a liquid frozen that produces 1 kg of energy?

gulaghasi [49]

Answer:

The correct option is C. 1 kJ x 1/ΔHfus x g/mol x ml/g liquid

Explanation:

The change in enthalpy of fusion (ΔHfus) has units of energy divided into moles of substance:

ΔHfus = energy/mol of substance = J/mol or KJ/mol

Thus, we multiply the kJ of energy produced by the inverse of ΔHfus (in kJ/mol) we obtain the moles of substance:

energy (kJ) x 1/ΔHfus (mol/kJ) = moles of substance(mol)

Then, if we multiply the moles of substance by the molecular weight of the substance (in g/mol) we obtain the grams:

moles of substance(mol) x molecular weight (g/mol) = grams of substance (g)

Finally, if we multiply the grams of substance (in g) by the density of the substance (in g/ml) we obtain the volume (in ml):

grams of substance (g) x 1/density (ml/g) = volume (ml)

We combine all these parts to obtain the equation for the volume required to produce 1 kJ of energy:

energy (kJ) x 1/ΔHfus (mol/kJ) x molecular weight (g/mol) x 1/density (ml/g)

Therefore, the correct option is:

C → 1 kJ x 1/ΔHfus x g/mol x ml/g liquid

5 0

3 years ago

Read 2 more answers