No, firstly bc stainless steel and carbon steel mixed with different things, high-density metals and carbon.
High-density metals and carbon both has different density which will affect the steel when they combined with iron. So it cant be the same.
Answer:
THE PRESSURE EXERTED BY THE GAS IS THEREFORE 2.88 atm.
Explanation:
Boyle's law states that at constant temperature, the volume of a given mass of gas is inversely proportional to the pressure of the gas.
Mathematically, P1 V1 = P2 V2
Write out the values of the variables given:
P1 = 2.4 atm
V1 = 1.8 L
V2 = 1.5 L
P2 = unknown
Re-arranging the variables by making P2 the subject of the equation, we have:
P2 = P1 V1 / V2
P2 = 2.4 * 1.8 / 1.5
P2 = 2.9=88 atm
Hence, the pressure exerted by the gas is therefore 2.88 atm
Answer:
why are you trying to find a date on a homework help website?
Answer:
The concentration of COF₂ at equilibrium is 0.296 M.
Explanation:
To solve this equilibrium problem we use an ICE Table. In this table, we recognize 3 stages: Initial(I), Change(C) and Equilibrium(E). In each row we record the <em>concentrations</em> or <em>changes in concentration</em> in that stage. For this reaction:
2 COF₂(g) ⇌ CO₂(g) + CF₄(g)
I 2.00 0 0
C -2x +x +x
E 2.00 - 2x x x
Then, we replace these equilibrium concentrations in the Kc expression, and solve for "x".
![Kc=8.30=\frac{[CO_{2}] \times [CF_{4}] }{[COF_{2}]^{2} } =\frac{x^{2} }{(2.00-2x)^{2} } \\8.30=(\frac{x}{2.00-2x} )^{2} \\\sqrt{8.30} =\frac{x}{2.00-2x}\\5.76-5.76x=x\\x=0.852](https://tex.z-dn.net/?f=Kc%3D8.30%3D%5Cfrac%7B%5BCO_%7B2%7D%5D%20%5Ctimes%20%5BCF_%7B4%7D%5D%20%7D%7B%5BCOF_%7B2%7D%5D%5E%7B2%7D%20%7D%20%3D%5Cfrac%7Bx%5E%7B2%7D%20%7D%7B%282.00-2x%29%5E%7B2%7D%20%7D%20%5C%5C8.30%3D%28%5Cfrac%7Bx%7D%7B2.00-2x%7D%20%29%5E%7B2%7D%20%5C%5C%5Csqrt%7B8.30%7D%20%3D%5Cfrac%7Bx%7D%7B2.00-2x%7D%5C%5C5.76-5.76x%3Dx%5C%5Cx%3D0.852)
The concentration of COF₂ at equilibrium is 2.00 -2x = 2.00 - 2 × 0.852 = 0.296 M
Answer:
B
Explanation:
B because I have a gut feeling
