An airplane flies eastward and always accelerates at a constant rate. at one position along its path it has a velocity of 26.3 m
/s, it then flies a further distance of 48100 m and afterwards its velocity is 41.9 m/s. find the airplane\'s acceleration and calculate how much time elapses while the airplane covers those 48100 m.
We will use the formula / equation to determined the time.
Distance = ½ * (vi + vf) * t 48100 = ½ * (26.3 + 41.9) * t t = 48100 ÷ 34.1 = 1410.557185 seconds
We will use the formula / equation to determined the acceleration.
vf = vi + a * t 41.9 = 26.3 + a * 1410.557185 a = (41.9 – 26.3) ÷ 1410.557185 = 0.011059459 m/s^2
We will use the formula / equation to determined the acceleration.
vf^2 = vi^2 + 2 * a * d 41.9^1 = 26.3^2 + 2 * a * 48100 a = (41.9^2 – 26.3^2) ÷ 96200 = 0. 011059459 m/s^2 Since both answers are the same, I believe the acceleration is correct.
For example, 1300 with a bar placed over the first 0 would have three significant figures (with the bar indicating that the number is precise to the nearest ten).
