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Vikki [24]
4 years ago
14

An airplane flies eastward and always accelerates at a constant rate. at one position along its path it has a velocity of 26.3 m

/s, it then flies a further distance of 48100 m and afterwards its velocity is 41.9 m/s. find the airplane\'s acceleration and calculate how much time elapses while the airplane covers those 48100 m.
Physics
1 answer:
galina1969 [7]4 years ago
6 0
We will use the formula / equation to determined the time.

Distance = ½ * (vi + vf) * t 
48100 = ½ * (26.3 + 41.9) * t 
t = 48100 ÷ 34.1 = 1410.557185 seconds 

We will use the formula / equation to determined the acceleration. 

vf = vi + a * t 
41.9 = 26.3 + a * 1410.557185 
a = (41.9 – 26.3) ÷ 1410.557185 = 0.011059459 m/s^2 

We will use the formula / equation to determined the acceleration.

vf^2 = vi^2 + 2 * a * d 
41.9^1 = 26.3^2 + 2 * a * 48100 
a = (41.9^2 – 26.3^2) ÷ 96200 = 0. 011059459 m/s^2 
Since both answers are the same, I believe the acceleration is correct.
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a moving cart hits a spring, traveling at 5.0 m/s at the time of contact. at this instant the cart is motionless by how much is
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A record turntable rotates through 5.0 rad in 2.8 s as it is accelerated uniformly from rest. What is the angular velocity at th
Usimov [2.4K]

Answer:

\omega_f = 3.584\ rad/s

Explanation:

given,

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now, using equation of rotational motion

\theta = \omega_i t + \dfrac{1}{2}\alpha t^2

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now, calculation of angular velocity

\omega_f = \omega_i + \alpha t

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3 years ago
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Reil [10]

Answer:

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F = 160N

3 0
3 years ago
Read 2 more answers
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