Answer:
The time taken to stop the box equals 1.33 seconds.
Explanation:
Since frictional force always acts opposite to the motion of the box we can find the acceleration that the force produces using newton's second law of motion as shown below:

Given mass of box = 5.0 kg
Frictional force = 30 N
thus

Now to find the time that the box requires to stop can be calculated by first equation of kinematics
The box will stop when it's final velocity becomes zero

Here acceleration is taken as negative since it opposes the motion of the box since frictional force always opposes motion.
Answer:
<em>The answer is medial!</em>
Explanation:
<em>The vertebral region is </em><u><em>medial</em></u><em> to the scapula.</em>
<em>Hope This Helps!</em>
<em>-</em><u><em>Justin:)</em></u>
Answer:
8) d
9) c
<em>Hope this helps! :)</em>
Given:
Circumference = 2 m
Angular speed, ω = 1 rev/s = 2π radians/s
If the radius is r, then
2πr = 2
r = 1/π m
The linear (tangential) speed is
v = rω
= (1/π m)*(2π rad/s) = 0.5 m/s
Answer: 0.5 m/s
Answer:
a) 665 kg.m/s
b) 2.97 kN
Explanation:
The impulse is given by:

where
va=velocity after
vb=velocity before
The velocity just before is given by:

The velocity just after is zero because there wasn't a rebound.
So the impulse is:

The impulse is also given by:
