Answer: Add an incline or grade to the road track.
Explanation:
Refer to the figure shown below.
When a vehicle travels on a level road in a circular path of radius r, a centrifugal force, F, tends to make the vehicle skid away from the center of the circular path.
The magnitude of the force is
F = mv²/r
where
m = mass of the vehicle
v = linear (tangential) velocity to the circular path.
The force that resists the skidding of the vehicle is provided by tractional frictional force at the tires, of magnitude
μN = μW = μmg
where
μ = dynamic coefficient of friction.
At high speeds, the frictional force will not overcome the centrifugal force, and the vehicle will skid.
When an incline of θ degrees is added to the road track, the frictional force is augmented by the component of the weight of the vehicle along the incline.
Therefore the force that opposes the centrifugal force becomes
μN + Wsinθ = W(sinθ + μ cosθ).
Answer:
D
Explanation:
According to newton's 2nd law rate of change of momentum is directly proportional to the force applied on the body. Since, net Force is zero this means momentum did not change or momentum of the body remained constant.
Hence, the system have constant value of momentum. Therefore, option D is correct.
Are there any options??
I would have to say metal of course but without options I can't assume anything
Answer:
d)21.5 moles
Explanation:
Given that
L = 24 L
T = 27 °C = 300 K
P = 22 atm
We know that ideal gas equation
P V = n R T
P=Pressure ,V= Volume ,n=Moles ,R=Universal gas constant ,T=Temperature
Now by putting the values
22 x 24 = n x 0.08206 x 300
n= 21.447 moles
n= 21.5 moles
Therefore the number of moles will be 21.5 moles.
The answer is "d".