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3 years ago

A submarine has a mass of 8,000,000 kg and is moving through the water at

Physics

1 answer:

Karo-lina-s [1.5K]3 years ago

6 0

Answer:

153760000 J

Explanation:

Kinetic energy is the energy possessed by a moving object solely due to its motion.

You can get the K.E. of an object using the equation,

K.E. = (1/2)mv²

So you get, for submarine,

K.E. = (1/2)×8000000×6.2²

= 153760000 J = 0.153 GJ

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What is the study of energy and how it affects matter called?

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3 years ago

Which will result in a greater increase in kinetic energy, doubling the velocity or doubling the mass.

Naddik [55]

Kinetic energy is the energy possessed by a body while in motion. It is calculated by 1/2mv², where m is the mass of the body and v is the velocity.
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3 years ago

I need a story about kepler's laws for a child, something a child would understand. And i'd like it to be okay for someone if I

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Answer:

(1) The orbits are ellipses, with focal points ƒ1 and ƒ2 for the first planet and ƒ1 and ƒ3 for the second planet. The Sun is placed in focal point ƒ1.

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8 0

2 years ago

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Two charged spheres are 20 cm apart and exert an attractive force of 8 x 10-9 n on each other. What will the force of attraction

Pavel [41]

Answer:

$3.2\cdot 10^{-8} N$

Explanation:

The inital electrostatic force between the two spheres is given by:

$F=k\frac{q_1 q_2}{r^2}$

where

$F=8\cdot 10^{-9} N$ is the initial force

k is the Coulomb's constant

q1 and q2 are the charges on the two spheres

r is the distance between the two spheres

The problem tells us that the two spheres are moved from a distance of r=20 cm to a distance of r'=10 cm. So we have

$r'=\frac{r}{2}$

Therefore, the new electrostatic force will be

$F'=k\frac{q_1 q_2}{(r')^2}=k\frac{q_1 q_2}{(r/2)^2}=4k\frac{q_1 q_2}{r^2}=4F$

So the force has increased by a factor 4. By using $F=8\cdot 10^{-9} N$ , we find

$F'=4(8\cdot 10^{-9} N)=3.2\cdot 10^{-8} N$

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2 years ago

Three charges 1.5*10-6, 3*10-6, -3*10-6 are placed at three vertices of an equilateral triangle of side 30cm. Find the net force

gulaghasi [49]

Answer:

F = 0N

Explanation:

The force between two charges is given by

$F=k\frac{q_1q_2}{r^2}$

where r is the distance between the charges and K is the Coulomb's constant

(k=8-89*10^9Nm^2/C^2)

The force in the first charge is only the sum of the forces due to the other charges. Hence we have

$F_T=F_1+F_2=k\frac{q_2q_1}{r^2}+k\frac{q_3q_1}{r^2}$

$F_T=(8.89*10^9\frac{Nm^2}{C^2})\frac{(3*10^{-6}C)(1.5*10^{-6}C)}{(0.3m)^2}+(8.89*10^9\frac{Nm^2}{C^2})\frac{(-3*10^{-6}C)(1.5*10^{-6}C)}{(0.3m)^2}\\\\F_T=0.445N-0.445N=0N$

Ft=0N

Hope this helps!!

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3 years ago

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