speed of the car is given on the road
reaction time is given as
now we can find the distance that it will move during this reaction time
now the deceleration of the car is 10 m/s^2
so the distance that it will move before stop is given by
so the total distance that it require to stop is given as
while the deer is standing at distance 38 m
so the car will stop 2.8 m before the position of deer
Answer:
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Explanation:
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Answer:
32500N
Explanation:
Data obtained from the question include:
m (mass) = 2500 kg
a (acceleration) = 13 m/s2
F (force) =?
Force is the product of mass and acceleration. It is represented mathematically as:
Force = mass x acceleration
F = m x a
With the above formula, the force with which the car strikes the barrier can be obtained as follow:
F = m x a
F = 2500 x 13
F = 32500N
Therefore, the car will strike the barrier with a force of 32500N
Answer:
13 m/s
Explanation:
I assume we are ignoring friction.
The boy's PE will all be converted to KE at the bottom of the hill.
to find PE = mgh we need to know h
h = 50 sin 10 = 8.68 meters
then: PE = 20 * 9.81 * 8.68 =<u> 1703.49</u> j
KE = 1/2 m v^2 = <u>1703 .49</u>
v = 13 m/s
