The force require to keep grouper submerged is 8.207N.
According to Archimedes principle buoyant force of any object must equal to weight of fluid it displaced.
The expression for the force exerted to stay submerged in salt water is
F = F(b) - w(fish)
where F(b) = buoyant force
w(fish) = weight
now substitute w(b) for F(b)
→ F = Vρg - w(fish)
where V = volume of sea water
ρ = density of sea water
Now by Archimedes principle V = m(fish) / ρ(fish)
→ F = (m(fish) / ρ (fish) ) ρg - m(fish)g
F = (85 kg/1015 kg-m^-3) (1.025× 10³ kg-m^-3) (9.8 m/s^2)
- (85kg) × 9.8 m/s^2
F = 841.207N - 833N
F = 8.207 N
Hence, the force require to keep grouper submerged is 8.207N.
Learn more about Archimedes Principle here:
brainly.com/question/15076878
#SPJ4
<span>the moon is a satellite of the earth, and the earth is a satellite of the sun.
that is the best answer</span>
The answer is c so the area can grow
Answer:
a. The station is rotating at ![1.496 \frac{rev}{min}](https://tex.z-dn.net/?f=%201.496%20%5Cfrac%7Brev%7D%7Bmin%7D)
b. the rotation needed is ![2.8502 \frac{rev}{min}](https://tex.z-dn.net/?f=%202.8502%20%5Cfrac%7Brev%7D%7Bmin%7D)
Explanation:
We know that the centripetal acceleration is
![a_{c}= \omega ^2 r](https://tex.z-dn.net/?f=a_%7Bc%7D%3D%20%5Comega%20%5E2%20r)
where
is the rotational speed and r is the radius. As the centripetal acceleration is feel like an centrifugal acceleration in the rotating frame of reference (be careful, as the rotating frame of reference is <u>NOT INERTIAL,</u> the centrifugal force is a fictitious force, the real force is the centripetal).
<h3>a. </h3>
The rotational speed is :
![2.7 \frac{m}{s^2} = \omega ^2 * 110 \ m](https://tex.z-dn.net/?f=2.7%20%5Cfrac%7Bm%7D%7Bs%5E2%7D%20%3D%20%5Comega%20%5E2%20%2A%20110%20%20%5C%20m)
![\omega ^2 = \frac{2.7 \frac{m}{s^2}} {110 \ m}](https://tex.z-dn.net/?f=%20%5Comega%20%5E2%20%3D%20%5Cfrac%7B2.7%20%5Cfrac%7Bm%7D%7Bs%5E2%7D%7D%20%7B110%20%5C%20m%7D%20)
![\omega = \sqrt{ 0.02454 \frac{rad^2}{s^2} }](https://tex.z-dn.net/?f=%20%5Comega%20%20%3D%20%5Csqrt%7B%200.02454%20%5Cfrac%7Brad%5E2%7D%7Bs%5E2%7D%20%7D%20)
![\omega = 0.1567 \frac{rad}{s}](https://tex.z-dn.net/?f=%20%5Comega%20%20%3D%200.1567%20%5Cfrac%7Brad%7D%7Bs%7D%20%20)
Knowing that there are
in a revolution and 60 seconds in a minute.
![\omega = 0.1567 \frac{rad}{s} \frac{1 \ rev}{2\pi \ rad} \frac{60 \ s}{1 \ min}](https://tex.z-dn.net/?f=%20%5Comega%20%20%3D%200.1567%20%5Cfrac%7Brad%7D%7Bs%7D%20%20%5Cfrac%7B1%20%5C%20rev%7D%7B2%5Cpi%20%5C%20rad%7D%20%5Cfrac%7B60%20%5C%20s%7D%7B1%20%5C%20min%7D)
![\omega = 1.496 \frac{rev}{min}](https://tex.z-dn.net/?f=%20%5Comega%20%20%3D%201.496%20%5Cfrac%7Brev%7D%7Bmin%7D)
<h3>b. </h3>
The rotational speed needed is :
![9.8 \frac{m}{s^2} = \omega ^2 * 110 \ m](https://tex.z-dn.net/?f=9.8%20%5Cfrac%7Bm%7D%7Bs%5E2%7D%20%3D%20%5Comega%20%5E2%20%2A%20110%20%20%5C%20m)
![\omega ^2 = \frac{9.8 \frac{m}{s^2}} {110 \ m}](https://tex.z-dn.net/?f=%20%5Comega%20%5E2%20%3D%20%5Cfrac%7B9.8%20%5Cfrac%7Bm%7D%7Bs%5E2%7D%7D%20%7B110%20%5C%20m%7D%20)
![\omega = \sqrt{ 0.08909 \frac{rad^2}{s^2} }](https://tex.z-dn.net/?f=%20%5Comega%20%20%3D%20%5Csqrt%7B%200.08909%20%5Cfrac%7Brad%5E2%7D%7Bs%5E2%7D%20%7D%20)
![\omega = 0.2985 \frac{rad}{s}](https://tex.z-dn.net/?f=%20%5Comega%20%20%3D%200.2985%20%5Cfrac%7Brad%7D%7Bs%7D%20%20)
Knowing that there are
in a revolution and 60 seconds in a minute.
![\omega = 0.2985 \frac{rev}{min} \frac{1 \ rev}{2\pi \ rad} \frac{60 \ s}{1 \ min}](https://tex.z-dn.net/?f=%20%5Comega%20%20%3D%200.2985%20%5Cfrac%7Brev%7D%7Bmin%7D%20%20%5Cfrac%7B1%20%5C%20rev%7D%7B2%5Cpi%20%5C%20rad%7D%20%5Cfrac%7B60%20%5C%20s%7D%7B1%20%5C%20min%7D%20)
![\omega = 2.8502 \frac{rev}{min}](https://tex.z-dn.net/?f=%20%5Comega%20%20%3D%202.8502%20%5Cfrac%7Brev%7D%7Bmin%7D)
These are the characteristics that apply:
- In a solution taste sour: which is consequence of the H+ concentration.
- Corrode metals: the H+ ion reacts with the metal producing a salt and water
-Produce hydronium ion in solution: as per the Bronsted - Lowry definition an acid is a substance that donates a proton, H+. This proton will react with H2O to form H3O+ (hydronium), as per this scheme:
HA + H2O --> A(-) + H3O(+)