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kondaur [170]
3 years ago
14

PLEASE ANSWER ASAP! SUPER IMPORTANT! GIVING POINTS!

Mathematics
1 answer:
katen-ka-za [31]3 years ago
4 0
-13 +16 = 3=odd+even = odd 

-7 + 16 = 9 =odd+even = odd 
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Write the following in expanded form then in word form . number 355,645​
valkas [14]

Answer:

300000+50000+5000+600+40+5

word form:- three lakh fifty five thousand six hundred forty five.

3 0
3 years ago
17 times 14 times 123
LUCKY_DIMON [66]

Answer:

29274

Step-by-step explanation:

Because 17*14=238 and 238*123=29274

8 0
3 years ago
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Is the answer English?
Vesnalui [34]
Yes indeed it is. Your correct
3 0
4 years ago
Write an expression that evaluates to true if the int associated with number_of_prizes is divisible (with no remainder) by the i
hodyreva [135]

We need to find the expression for " number_of_prizes is divisible number_of_participants". Also there should not remain any remainder left. On in order words, we can say the reaminder we get after division is 0.

Let us assume number of Prizes are = p and

Number of participants = n.

If we divide number of Prizes by number of participants and there will be not remainder then there would be some quotient remaining and that quotent would be a whole number.

Let us assume that quotent is taken by q.

So, we can setup an expression now.

Let us rephrase the statement .

" Number of Prizes ÷ Number of participants  = quotient".

p ÷ n = q.

In fraction form we can write

p/n =q   ; n ≠ 0.


4 0
3 years ago
The Venn diagram shows the results of two events resulting from rolling a number cube.
gulaghasi [49]

Answer:   P(A\cap B)=\frac{1}{3}

P(A)=\frac{1}{3}

P(B)=1

P(A|B)=\frac{1}{3}

Step-by-step explanation:

From the given figure it can be seen that

Total number on cube= n(S)=6

Intersection of A and B = n(A ∩ B)= 2

Therefore,

P(A\cap B)=\frac{n(A\cap B)}{n(s)}=\frac{2}{6}=\frac{1}{3}

Also, The number of elements in A = 2

Therefore,

P(A)=\frac{n(A)}{n(s)}=\frac{2}{6}=\frac{1}{3}

Similarly, The number of elements in B= 6

Therefore,

P(B)=\frac{n(B)}{n(s)}=\frac{6}{6}=1

The formula to find the conditional probability is given by :-

P(A|B)=\frac{P(A\cap B)}{P(B)}\\\\\Rightarrow P(A|B)=\frac{\frac{1}{3}}{1}=\frac{1}{3}

4 0
4 years ago
Read 2 more answers
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