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SVEN [57.7K]
2 years ago
6

A salt lover decided to flavor her meal by adding 2.50 moles of sodium chloride,

Chemistry
1 answer:
FromTheMoon [43]2 years ago
4 0

Answer: C, 146

Explanation:

NaCl has a molar mass of 58.44 g/mol.

To change moles to g, we do:

2.50 moles × 58.44 g/mol = 146.1 g, so C

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ASAP I AM GIVING BRAINLIEST PLEASEEEEEEEEE HELPPPPPPPPPPPPPPPPPP
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Answer:

B?

Explanation:

In the example, the amount of hydrogen is 202,650 x 0.025 / 293.15 x 8.314472 = 2.078 moles. Use the mass of the hydrogen gas to calculate the gas moles directly; divide the hydrogen weight by its molar mass of 2 g/mole. For example, 250 grams (g) of the hydrogen gas corresponds to 250 g / 2 g/mole = 125 moles.

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3 years ago
Which statements are correct regarding the Law of Conservation of Matter and Energy?
Elden [556K]

Answer:

Matter or energy can change from one form to the other

Explanation:

The law of conservation of energy states that energy can neither be created nor destroyed but can only be transformed i.e. changed from one form to another. For example, mechanical energy can be changed to electrical energy.

Likewise, the law of conservation of mass/matter states that matter can not be destroyed or created but can change via physical or chemical means to conserve it. For example, matter can change from liquid state to gaseous state.

From the above two laws, it can be said that "matter or energy can change from one form to the other".

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3 years ago
As a result of the gold foil experiment, it was concluded that an atom(1) contains protons, neutrons, and electrons(2) contains
grin007 [14]
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What amount of heat is released when the temperature of 450.0 g of a
Molodets [167]

Answer:

\boxed {\boxed {\sf 4038.48 \ Joules}}

Explanation:

Since we are given the mass, specific heat, and change in temperature, we should use this formula for heat:

q=mc\Delta T

The substance's mass is 450.0 grams, the specific heat is 1.264 J/g°C, and the  change in temperature is 7.1 °C.

m= 450.0 \ g \\c= 1.264 \ J/g \textdegree C\\\Delta T= 7.1 \ \textdegree C

Substitute the values into the formula.

q= (450.0 \ g)(1.264 \ J/g \textdegree C)(7.1 \ \textdegree C)

Multiply the first 2 values together. The grams will cancel out.

q= 568.8 \ J/ \textdegree C (7.1 \ \textdegree C)

Multiply again. This time, the degrees Celsius cancel out.

q= 4038.48 \ J

<u>4038.48 Joules</u> of heat energy are released.

5 0
2 years ago
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