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kkurt [141]
3 years ago
13

A base _____. A.accepts hydrogen ions, B.releases hydrogen ions, C.accepts hydrogen atoms

Chemistry
2 answers:
xxMikexx [17]3 years ago
5 0
<span>C.accepts hydrogen atoms
i think
</span>
Triss [41]3 years ago
5 0

Answer:

The correct option is A

Explanation:

A base is usually defined as a substance that produces hydroxyl/hydroxide ion (OH-) as the only negative ion when dissolved in water. However, Bronsted Lowry defined a base as a chemical substance that can accept a proton/hydrogen ion. Example of a Bronsted Lowry base is ammonia (NH₃).

Ammonia (NH₃) when dissolved in water (H₂O) forms Ammonium ion (NH₄+) and hydroxide ion.

NH₃ + H₂O ⇔ NH₄⁺  +  OH⁻

From the equation above, we can see that ammonia (NH₃) accepts a hydrogen ion to become ammonium ion (NH₄⁺).

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The molar mass and molecular weight of Al(CH3CO2)3 is 204.1136.

Explanation:

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Cesium sulfite is formed from the cs cation and the so2−3 anion. What is the correct formula for this compound?
Anna35 [415]

Cesium Sulfite is formed from the Cs cation and the SO₃⁻² anion. The correct formula for this compound is Cs₂SO₃.

<h3>What is Cation ? </h3>

Cations are positively charged ions. It forms when an element lose one or more electrons.

<h3>
What is Anion ? </h3>

Anions are negatively charged ions. It form when an element gains one or more electrons.

Symbol         Cs⁺¹         SO₃⁻²

Valency           +1              -2

Formula of the compound is Cs₂SO₃.

Thus from the above conclusion we can say that Cesium Sulfite is formed from the Cs cation and the SO₃⁻² anion. The correct formula for this compound is Cs₂SO₃.

Learn more about the Cation and Anions here: brainly.com/question/20005547
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3 0
1 year ago
What is the specific heat of a 44 g piece of metal if 202 Joules of heat are required to
Ray Of Light [21]

Answer:

≈ 395,8 J/(kg * °C)

Explanation:

m = 44 g = 0,044 kg

t_{1} = 22 °C

t_{2} = 33,6 °C

Q = 202 J

The formula is: Q = c * m * (t_{2} - t_{1})

c = \frac{Q}{m * (t_{2} - t_{1} )}

Calculating:

c = 202 J / 0,044 kg * (33,6 °C - 22 °C) ≈ 395,8 J/(kg * °C)

4 0
3 years ago
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