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Anvisha [2.4K]
3 years ago
8

What is the specific heat of a 44 g piece of metal if 202 Joules of heat are required to

Chemistry
1 answer:
Ray Of Light [21]3 years ago
4 0

Answer:

≈ 395,8 J/(kg * °C)

Explanation:

m = 44 g = 0,044 kg

t_{1} = 22 °C

t_{2} = 33,6 °C

Q = 202 J

The formula is: Q = c * m * (t_{2} - t_{1})

c = \frac{Q}{m * (t_{2} - t_{1} )}

Calculating:

c = 202 J / 0,044 kg * (33,6 °C - 22 °C) ≈ 395,8 J/(kg * °C)

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