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Eva8 [605]
2 years ago
11

A sample of 0.0860 g of sodium chloride is added to 30.0 mL of 0.050 M silver nitrate, resulting in the formation of a precipita

te. (a) Write the molecular equation for the reaction. (b) What is the limiting reactant in the reaction? (c) How many grams of precipitate potentially form?
Chemistry
1 answer:
Grace [21]2 years ago
3 0

Answer:

0.21 g

Explanation:

The equation of the reaction is;

NaCl(aq) + AgNO3(aq) -----> NaNO3(aq) + AgCl(s)

Number of moles of NaCl= 0.0860 g /58.5 g/mol = 0.00147 moles

Number of moles of AgNO3 = 30/1000 L × 0.050 M = 0.0015 moles

Since the reaction is 1:1, NaCl is the limiting reactant.

1 mole of NaCl yields 1 mole of AgCl

0.00147 moles of NaCl yields 0.00147 moles of AgCl

Mass of precipitate formed = 0.00147 moles of AgCl × 143.32 g/mol

= 0.21 g

You might be interested in
How many grams are there in 3.30x10 23 grams of n2i6
qwelly [4]
Technically, the answer should be 3.30 * 10^23 grams. But I think you mean either molecules, atoms, moles or grams of Ni2I6 with that number of molecules .

1 mole of Ni2 I6  = 6.02 * 10^23 molecules
x  [mole] = 3.30 * 10^23 molecules

1/x = 6.02 * 10^23 / 3.30 * 10^23 Cancel the 10^23 on the right side
1/x = 6.02 / 3.30 Cross multiply
3.30 = 6.02 x Divide by 6.02
3.30 / 6.02 = x 
x = 0.548 moles 

what to do from here?

1 mole of Ni2I6 is
2 * Ni = 2 * 59 = 118 grams
6 *  I = 6 * 131 = <u>786 grams</u>
Total  =               904 grams

Set up a proportion.
<u>1 mole Ni2I6 </u>  = <u>904 grams</u>  
0.548 moles    = x

1/0.548 = 904/x Cross multiply
x = 0.548 * 904
x = 495.4 grams of Ni2I6 <<<<<< Answer.

8 0
3 years ago
Can someone please answer this?
Amanda [17]

Answer:-

0.229 L

Explanation:-

Molar mass of AgBr = 107.87 x 1 + 79.9 x 1

=187.77 grams mol-1

Mass of AgBr = 150 grams

Number of moles of AgBr = 150 grams / 187.77 gram mol-1

= 0.8 mol

The balanced chemical equation is

NaBr (aq) + AgNO3 (aq)--> AgBr(s) + NaNO3(aq)

From the equation we can see that

1 mol of AgBr is produced from 1 mol of AgNO3.

∴ 0.8 mol of AgBr is produced from 1 x 0.8 / 1 = 0.8 mol of AgNO3.

Strength of AgNO3 = 3.5 M

Volume of AgNO3 required = Number of moles / strength

= 0.8 moles / 3.5

=0.229 L

8 0
3 years ago
4.
telo118 [61]

The series which is in order of increasing boiling point is CH3CH2CH3 CH3COCH3 CH2CH2CH3OH

However, the boiling point of an organic substance is the temperature at which the vapor pressure of the liquid organic substance equals the pressure surrounding the liquid and the liquid changes into a vapor.

<h3>What are organic compounds?</h3>

Organic compounds are substance containing carbon and hydrogen. Some few organic compounds include:

  • Alkanes
  • Alkenes
  • Alkynes
  • Alkanols
  • Alkanals
  • Alkanones
  • Esters
  • Amines

So therefore, the series which is in order of increasing boiling point is CH3CH2CH3 CH3COCH3 CH2CH2CH3OH

Learn more about organic compounds:

brainly.com/question/704297

8 0
1 year ago
Calculate the molarity of 48.0 mL of 6.00 M H2SO4 diluted to 0.250 L
const2013 [10]

Answer:

The answer is 1.15m.

Since molality is defined as moles of solute divided by kg of solvent, we need to calculated the moles of H2SO4 and the mass of the solvent, which I presume is water.

We can find the number of H2SO4 moles by using its molarity

C=nV→nH2SO4=C⋅VH2SO4=6.00molesL⋅48.0⋅10−3L=0.288

Since water has a density of 1.00kgL, the mass of solvent is

m=ρ⋅Vwater=1.00kgL⋅0.250L=0.250 kg

Therefore, molality is

m=nmass.solvent=0.288moles0.250kg=1.15m

4 0
3 years ago
Read 2 more answers
A molecule has the empirical formula C4H6O. If its molecular weight is determined to be about 212 g/mol, what is the most likely
krok68 [10]

Answer:

The molecular formula is C12H18O3

Explanation:

Step 1: Data given

The empirical formula is C4H6O

Molecular weight is 212 g/mol

atomic mass of C = 12 g/mol

atomic mass of H = 1 g/mol

atomic mass of O = 16 g/mol

Step 2: Calculate the molar mass of the empirical formula

Molar mass = 4* 12 + 6*1 +16

Molar mass = 70 g/mol

Step 3: Calculate the molecular formula

We have to multiply the empirical formula by n

n = the molecular weight of the empirical formula / the molecular weight of the molecular formula

n = 70 /212 ≈ 3

We have to multiply the empirical formula by 3

3*(C4H6O- = C12H18O3

The molecular formula is C12H18O3

3 0
3 years ago
Read 2 more answers
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