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4 years ago

How many valence electrons does copper contain?

1 answer:

8 0

Copper has 29 electrons, and its electron configuration is:
1s2 2s2 2p6 3s2 3p6 3d10 4s1.

Therefore, copper has 1 valence electron.

Hope this helps~

You might be interested in

What is the temperature (in K) of 16.45 moles of methane gas in a 4.95 L container at 4.68 atm?

AlexFokin [52]

Using the ideal gas law: PV=nRT
P is pressure; V is volume; n is the amount in moles; R=0.082; T is temperature in K.

(4.68)*(4.95)=(16.45)*(0.0821)*T
Solve for T.
T=17.15

4 0

4 years ago

Phosphorus pentachloride decomposes according to this equation. PCl5(g) equilibrium reaction arrow PCl3(g) + Cl2(g) An equilibri

melisa1 [442]

Answer:

PCl₅ = 0.03 X 208 = 6.24g

PCl₃ = 0.05 X 137 =6.85 g

Cl₂ = 0.03X71 = 2.13 g

Explanation:

The equilibrium constant will remain the same irrespective of the amount of reactant taken.

Let us calculate the equilibrium constant of the reaction.

Kc= $\frac{[PCl_{3}][Cl_{2}]}{[PCl_{5}]}$

Let us calculate the moles of each present at equilibrium

$moles=\frac{mass}{molarmass}$

molar mass of PCl₅=208

molar mass of PCl₃=137

molar mass of Cl₂=71

moles of PCl₅ = $\frac{mass}{molarmass}=\frac{4.13}{208}=0.02$

moles of PCl₃= $\frac{mass}{molarmass}=\frac{8.87}{137}=0.06$

moles of Cl₂ = $\frac{mass}{molarmass}=\frac{2.90}{71}=0.04$

the volume is 5 L

So concentration will be moles per unit volume

Putting values

Kc = $\frac{\frac{0.06}{5}\frac{0.04}{5}}{\frac{0.02}{5}}=0.024$

Now if the same moles are being transferred in another beaker of volume 2L then there will change in the concentration of each as follow

$PCl_{5}--->PCl_{3}+Cl_{2}$

Initial 0.02 0.06 0.04

Change -x +x +x

Equilibrium 0.02-x 0.06+x 0.04+x

Conc. (0.02-x)/2 (0.06+x)/2 (0.04+x)/2

Putting values

0.024 = $\frac{(0.06+x)(0.04+x)}{(0.02-x)2}$

Solving

$(0.024(2)(0.02-x)=(0.06+x)(0.04+x)$

$0.00096-0.048x=0.0024+x^{2}+0.1x$

$0.148x+x^{2}+0.00144=0$

x = -0.01

so the new moles of

PCl₅ = 0.02 + 0.01 =0.03

PCl₃ = 0.06-0.01 = 0.05

Cl₂ = 0.04-0.01 = 0.03

mass of each will be:

mass= moles X molar mass

PCl₅ = 0.03 X 208 = 6.24g

PCl₃ = 0.05 X 137 =6.85 g

Cl₂ = 0.03X71 = 2.13 g

5 0

3 years ago

What is the volume of 90.0 g of ether if the density of the ether is 0.70 g/mL?

natali 33 [55]

Mass = 90.0 g

Density = 0.70 g/mL

Volume = in mL ?

D = m / V

0.70 = 90.0 / V

V = 90.0 / 0.70

V = 128.57 mL

5 0

3 years ago

Helppppppppppppppppppppppppppppppppppppp

stealth61 [152]

Answer:

0.67moles

Explanation:

The balanced equation of the chemical reaction given in this question is:

N2 + 3H2 → 2NH3

According to this equation, 3 moles of hydrogen gas (H2) produces 2 moles of ammonia gas (NH3)

Therefore, 1 mole of hydrogen gas (H2) will produce;

= 1 × 2/3

= 2/3

= 0.6666

= 0.67moles of ammonia (NH3)

6 0

3 years ago

According to the following reaction, how many grams of ammonia will be formed upon the complete reaction of 31.2 grams of hydrog

Aneli [31]

Answer:

176.8 g of ammonia, NH3.

Explanation:

We'll begin by writing the balanced equation for the reaction. This is given below:

N2 + 3H2 —> 2NH3

Next, we shall determine the mass of H2 that reacted and the mass of NH3 produced from the balanced equation. This is illustrated below:

Molar mass of H2 = 2x1 = 2 g/mol

Mass of H2 from the balanced equation = 3 x 2 = 6 g

Molar mass of NH3 = 14 + (3x1) = 17 g/mol

Mass of NH3 from the balanced equation = 2 x 17 = 34 g.

From the balanced equation above,

6 g of H2 reacted to produce 34 g of NH3.

Finally, we shall determine the mass of ammonia, NH3 produced by reacting 31.2 g of H2.

This can be obtained as follow:

From the balanced equation above,

6 g of H2 reacted to produce 34 g of NH3.

Therefore, 31.2 g of H2 will react to produce = (31.2 x 34)/6 = 176.8 g of NH3.

Therefore, 176.8 g of ammonia, NH3 were obtained from the reaction.

8 0

3 years ago