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Debora [2.8K]
3 years ago
5

The explosions that take place during a fireworks show are an example of which of the following?Image of fireworks exploding in

air
Chemical change
Chemical property
Physical change
Physical property
Chemistry
2 answers:
MatroZZZ [7]3 years ago
5 0

Answer:

Chemical change

Explanation:

A chemical change is a change that cannot be reversed. It results in the formation of a new product. For example, the combustion of wood gives carbon dioxide and water and sometimes suit. In other words, in a chemical change, the products are always different from the reactants. The following equation generally governs a chemical change:

Reactants = Products (solid, liquid, or gas)

babymother [125]3 years ago
4 0
Chemical change
:)
hope this helps
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How many moles of calcium, Ca, are in 5.00 g of calcium?
Rom4ik [11]
<h3>Answer:</h3>

0.125 mol Ca

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

<u>Chemistry</u>

<u>Atomic Structure</u>

  • Reading a Periodic Table
  • Using Dimensional Analysis
<h3>Explanation:</h3>

<u>Step 1: Define</u>

5.00 g Ca

<u>Step 2: Identify Conversions</u>

Molar mass of Ca - 40.08 g/mol

<u>Step 3: Convert</u>

  1. Set up:                               \displaystyle 5.00 \ g \ Ca(\frac{1 \ mol \ Ca}{40.08 \ g \ Ca})
  2. Multiply:                             \displaystyle 0.12475 \ mol \ Ca

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 3 sig figs.</em>

0.12475 mol Ca ≈ 0.125 mol Ca

3 0
2 years ago
A 13.00 g sample of a compound contains 4.15 g potassium (k), 3.76 g chlorine (cl), and oxygen (o). calculate the empirical form
MrRissso [65]

To solve this problem, let us all convert the mass of each element into number of moles using the formula:

moles = mass / molar mass

Where,

molar mass K = 39.10 g / mol

<span>molar mass Cl = 35.45 g / mol</span>

molar mass O = 16 g / mol

<span>and mass O = 13 g – 4.15 g – 3.76 g  = 5.09 g</span>

 

moles K = 4.15 g / (39.10 g / mol) = 0.106 mol

<span>moles Cl = 3.76 g / (35.45 g / mol) = 0.106 mol</span>

moles O = 5.09 g / (16 g / mol) = 0.318 mol

 

The ratio becomes:

0.106 K: 0.106 Cl: 0.318 O

We divide all numbers with the smallest number, in this case 0.106. This becomes:

K: Cl: 3O

 

Therefore the empirical formula is:

KClO_{3}

7 0
2 years ago
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