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Vedmedyk [2.9K]
3 years ago
11

*****

Chemistry
1 answer:
FromTheMoon [43]3 years ago
8 0
Lol that’s sad lollllllllllllllllllllp
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The pH of a solution that is formed by the neutralization of 1.0M H2SO4(aq) and 1.0 M KOH(aq) is closest to
pshichka [43]

Answer:

b) 7

Explanation:

The pH of a solution produced by the neutralization reaction between 1M of H₂SO₄ and KOH with 1M is closest to 7.

pH is a standard for measuring the acidity and alkalinity of a solution. A solution that is acidic will have a pH less than 7, a neutral solution will have pH of 7 and a basic solution will have pH greater than 7.

What is a neutralization reaction?

  • It is an acid-base reaction in which hydrogen and hydroxide ions combines to form water.
  • Also a salt results from the combination of the other ions.

In this reaction a base simply neutralizes an acid and the solution becomes neutral before it goes into completion.

Therefore, a neutral solution will have pH of 7 or close to it.

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3 years ago
A photon of green light strikes an unknown metal and an electron is emitted. The voltage is set to 2 volts. The electron cannot
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Answer:

The correct answer is:

An electron will be emitted in the second experiment, but it cannot be determined whether it will reach the second plate.

Explanation:

In fact, violet has higher frequency than green light. This means that photons on violet carry more energy than photons of green light (remember that the energy of a photon is proportional to it's frequency:

e = hf

, so when they hit the surface of the metal, more energy is transferred to the electrons. The electron was already emitted with green light, so it must be emitted with also violet light, given the more energy transferred.

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What is the mass of a sample of NH3 containing 7.20 x 10^24 molecules of NH3?
leva [86]

Answer:203

Explanation: just have to timez

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What is the name of this compound?
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Answer:

B. ethylamine.

Explanation:

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  • The alkyl group C₂H₅- contains 2 C atoms (ethyl group).

<em>So, the compound is ethylamine.</em>

<em />

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