Answer:
H+(aq) + OH-(aq) ⟶H2O(l)
Explanation:
Step 1: The balanced equation
HCN(aq) + KOH(aq) ⟶ H2O (l) + KCN (aq)
H+(aq) + CN-(aq) + K+(aq) + OH-(aq) ⟶H2O(l) + K+(aq) + CN-(aq)
Step 2: The net ionic equation
The net ionic equation, for which spectator ions are omitted - remember that spectator ions are those ions located on both sides of the equation - will , after canceling those spectator ions in both side, look like this:
H+(aq) + OH-(aq) ⟶H2O(l)
Answer:
Both reactions share a common intermediate and differ only in the leaving group
Explanation:
The elimination reaction of tertiary alkyl halides usually occur by E1 mechanism. In E1 mechanism, the substrate undergoes ionization leading to the loss of a leaving group and formation of a carbocation.
Loss of a proton from the carbocation completes the reaction mechanism yielding the desired alkene.
In the cases of t-butanol and t-butyl bromide, the mechanism is the same. The both reactions proceed by E1 mechanism. The leaving groups in each case are water and chloride ion respectively.
Answer:
neutral
Explanation:
There are three basic subatomic particles. These are;
- Protons (positively charged)
- Electrons (negatively charged)
- Neutrons (neutral)
A neutron has no charge unlike the proton and the electron. It is present in the nucleus and contributes to the mass of the atom.
Hey there!
Volume in mL :
1.68 L * 1000 => 1680 mL
Density = 0.921 g/mL
Therefore:
Mass = density * Volume
Mass = 0.921 * 1680
Mass = 1547.28 g
